AQA Core 2 MPC2 22/05/2009

I'm sure I got x=9 and y=192 or something...
But I did get the length as 0.6 as it was 9 - 8.4

For the sum to infinity question, starting with the 6th term. Is this a valid method? because others did as the sum to infity of the series - the sum of terms from 1-5.

I did this =

U6 = 625x0.6^(6-1) = 48.6
Sum to infity = 48/ (1-0.6) = 121.5..

For the sum to infinity question, starting with the 6th term. Is this a valid method? because others did as the sum to infity of the series - the sum of terms from 1-5.

I did this =

U6 = 625x0.6^(6-1) = 48.6
Sum to infity = 48/ (1-0.6) = 121.5..

do you think i will loose marks for leaving

y= root ((2x)^3 + 1)

Oh yeah, that's what I got. Not sure where I got the 2 from...

For the question about transformations, I put:

$\sqrt(2x)^3 + 1$

Do you think I'd still get the marks, even though I didn't put $\sqrt8x^3 + 1$ ?



I did it like this. I think we'll get the marks. It's a just as valid method as the other way...

erm 2 marks could mean,

1 mark knowing it is 2, because of stretching of 1/2

1 mark for knowing where to put the two

we could still have got 2 marks!

For the sum to infinity question, starting with the 6th term. Is this a valid method? because others did as the sum to infity of the series - the sum of terms from 1-5.

I did this =

U6 = 625x0.6^(6-1) = 48.6
Sum to infity = 48/ (1-0.6) = 121.5..

do you think i will loose marks for leaving

y= root ((2x)^3 + 1)

erm 2 marks could mean,

1 mark knowing it is 2, because of stretching of 1/2

1 mark for knowing where to put the two

we could still have got 2 marks!

I think I got 30 and 150 degrees..

Yeah I used the formula.

And 270... because a solution was also sinx = -1

so x = -90

and 180- -90 = 270

I got 30, 150, and 270 degrees.

And I think using the forumla is valid, I just did it as solving it as a quadratic. Giving two equations for sin. Sin x = 1/2 and Sin x = -1

then I solved each seperately to give the values. I rejectd -90, because the intervall only said 0<x<360.