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# Maths question watch

1. a) Defferenciate x^(x^2) with respect to x

is this **** done in further maths
2. (Original post by matouwah)
a) Defferenciate x^(x^2) with respect to x

is this **** done in further maths

what module is it?
3. (Original post by matouwah)
a) Defferenciate x^(x^2) with respect to x

is this **** done in further maths
let y=x^2

(1/y)y'=2xlnx + x (d/dx on both sides)

=> y'= x^(x^2)[2xlnx+x]
4. (Original post by ShOcKzZ)
what module is it?
dunno....some guy doing the course i want to do at oxford was asked it during the interview....but he was doing further maths.....i havent ecountered this type of question on p3....and i'm not doing further maths...
5. (Original post by M Safe)
let y=x^2

(1/y)y'=2xlnx + x (d/dx on both sides)

=> y'= x^(x^2)[2xlnx+x]
sorry y=x^(x^2)
6. (Original post by M Safe)
let y=x^2

(1/y)y'=2xlnx + x (d/dx on both sides)

=> y'= x^(x^2)[2xlnx+x]
uhmmm.....kinda lost....could u explain it in more detail...i am a bit of a retard.....thanx...
7. (Original post by matouwah)
uhmmm.....kinda lost....could u explain it in more detail...i am a bit of a retard.....thanx...
y=x^(x^2)

ln y = (x^2)ln(x)

differentiate wrt x on both sides (dy/dx = d/dy * dy/dx)

so 1/y * (dy/dx) = x + 2xln(x) (use product rule to obtain RHS)

do dy/dx = y(x+2xln(x))
= ...
8. (Original post by M Safe)
y=x^(x^2)

ln y = (x^2)ln(x)

differentiate wrt x on both sides (dy/dx = d/dy * dy/dx)

so 1/y * (dy/dx) = x + 2xln(x) (use product rule to obtain RHS)

do dy/dx = y(x+2xln(x))
= ...

ahhhhh i see it now.....thanx...
9. take logs.
10. i once differentiated x^x^x "for fun". woohoo the hilarity! (i was bored in a free period). i then went on to do x^x^x^x, and their integrals. god i am sad.

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