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matouwah
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#1
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#1
a) Defferenciate x^(x^2) with respect to x

is this **** done in further maths
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ShOcKzZ
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(Original post by matouwah)
a) Defferenciate x^(x^2) with respect to x

is this **** done in further maths

what module is it?
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M Safe
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#3
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(Original post by matouwah)
a) Defferenciate x^(x^2) with respect to x

is this **** done in further maths
let y=x^2

(1/y)y'=2xlnx + x (d/dx on both sides)

=> y'= x^(x^2)[2xlnx+x]
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matouwah
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(Original post by ShOcKzZ)
what module is it?
dunno....some guy doing the course i want to do at oxford was asked it during the interview....but he was doing further maths.....i havent ecountered this type of question on p3....and i'm not doing further maths...
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M Safe
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(Original post by M Safe)
let y=x^2

(1/y)y'=2xlnx + x (d/dx on both sides)

=> y'= x^(x^2)[2xlnx+x]
sorry y=x^(x^2)
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matouwah
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(Original post by M Safe)
let y=x^2

(1/y)y'=2xlnx + x (d/dx on both sides)

=> y'= x^(x^2)[2xlnx+x]
uhmmm.....kinda lost....could u explain it in more detail...i am a bit of a retard.....thanx...
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M Safe
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(Original post by matouwah)
uhmmm.....kinda lost....could u explain it in more detail...i am a bit of a retard.....thanx...
y=x^(x^2)

ln y = (x^2)ln(x)

differentiate wrt x on both sides (dy/dx = d/dy * dy/dx)

so 1/y * (dy/dx) = x + 2xln(x) (use product rule to obtain RHS)

do dy/dx = y(x+2xln(x))
= ...
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matouwah
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(Original post by M Safe)
y=x^(x^2)

ln y = (x^2)ln(x)

differentiate wrt x on both sides (dy/dx = d/dy * dy/dx)

so 1/y * (dy/dx) = x + 2xln(x) (use product rule to obtain RHS)

do dy/dx = y(x+2xln(x))
= ...

ahhhhh i see it now.....thanx...
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Bigcnee
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#9
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take logs.
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elpaw
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#10
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i once differentiated x^x^x "for fun". woohoo the hilarity! (i was bored in a free period). i then went on to do x^x^x^x, and their integrals. god i am sad.
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