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Differential Equations

I am struggling a bit at the moment with differential equations, and wondering if anyone could help me with the following questions.

Given that y(o) = 50

y(t) + 0.5y(t-1) = 6

verify using t = 1 and t = 0 and analyze the stability of the system.

Describe in the nature of the time path and produce a graph of the latter

Thank you for your help i advance, and if you recommend any websites where i could further my knowledge it would be much appreciated
Reply 1
Are you able to write down y(1), y(2), etc?
Reply 2
Original post by BabyMaths
Are you able to write down y(1), y(2), etc?


i get y(t)=-23^t + 4 but i have a feeling thats really wrong
Reply 3
Original post by BabyMaths
Are you able to write down y(1), y(2), etc?


i get y= -19 and y(2) = 15.5
Reply 4
Original post by ilikemaths1
i get y= -19 and y(2) = 15.5


Keep going.

Do it on a calculator.

50=

6-ANS/2
=
=
=
....eventually...?
Reply 5
Original post by BabyMaths
Keep going.

Do it on a calculator.

50=

6-ANS/2
=
=
=
....eventually...?


eventually 4, what does that show?
Reply 6
You are asked to describe etc..

BTW, is part of the question missing?
Reply 7
Original post by BabyMaths
You are asked to describe etc..

BTW, is part of the question missing?


how do you verify the answer?

and the nature bit? :/

And onpe that seems to be all of it
Reply 8
Strange. If that's the whole question there doesn't seem to be anything to verify.

Your thread title suggests there should be a differential equation knocking around somewhere.

With just the behavior at t=0,1,2,3,4.. what can we say? It settles down to y=4 but what is y when t=101.1?

Sorry. I'm babbling.
Reply 9
Original post by BabyMaths
Strange. If that's the whole question there doesn't seem to be anything to verify.

Your thread title suggests there should be a differential equation knocking around somewhere.

With just the behavior at t=0,1,2,3,4.. what can we say? It settles down to y=4 but what is y when t=101.1?

Sorry. I'm babbling.


oh okay no problem, what you said was helpful anyways so thank you

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