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geometric sequence quick question AS

hmm not sure if I've posted this thought I did but then I checked the recent posts in the maths forum but can't see mine.

please see attatchred having trouble figuing out how to use thee equations I've formed to show what they want me to show
Your first equation divided by your second equation = the "show that" equation.

Simple :smile:
Reply 2
Original post by CasualSoul
hmm not sure if I've posted this thought I did but then I checked the recent posts in the maths forum but can't see mine.

please see attatchred having trouble figuing out how to use thee equations I've formed to show what they want me to show


a(1r3)1r=a1r×(1r3)\dfrac{a(1-r^3)}{1-r} = \dfrac{a}{1-r} \times (1-r^3)
Reply 3
Original post by The Polymath
Your first equation divided by your second equation = the "show that" equation.

Simple :smile:


oh right yeah I understand that
Original post by TenOfThem
a(1r3)1r=a1r×(1r3)\dfrac{a(1-r^3)}{1-r} = \dfrac{a}{1-r} \times (1-r^3)


your method is neat:biggrin: but I don't see what you've done. I see that you've put the first equation equal to something else but please could you explain where the 'something else bit' has come from
Original post by CasualSoul
oh right yeah I understand that


your method is neat:biggrin: but I don't see what you've done. I see that you've put the first equation equal to something else but please could you explain where the 'something else bit' has come from


He's literally done what I said.

Equation 1 = a(1-r^3)/(1-r)
Equation 2 = a/(1-r)
Equation 3 = (1-r^3)

Equation 1 / Equation 2 = Equation 3

So Equation 1 = Equation 2 x Equation 3 <- this is what he wrote
Reply 5
Original post by The Polymath
He's literally done what I said.

Equation 1 = a(1-r^3)/(1-r)
Equation 2 = a/(1-r)
Equation 3 = (1-r^3)

Equation 1 / Equation 2 = Equation 3

So Equation 1 = Equation 2 x Equation 3 <- this is what he wrote


Ta :smile:
Reply 6
Original post by The Polymath
He's literally done what I said.

Equation 1 = a(1-r^3)/(1-r)
Equation 2 = a/(1-r)
Equation 3 = (1-r^3)

Equation 1 / Equation 2 = Equation 3

So Equation 1 = Equation 2 x Equation 3 <- this is what he wrote


And it was all the more impressive as I had a sex change whilst doing it

Apparently

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