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Reply 180
Original post by Choppie
Thanks! Both of you are legends!


No prob :smile:
Original post by Choppie
Thanks! Both of you are legends!


:angelblush: thanks ;(
Reply 182
Original post by L'Evil Fish
:angelblush: thanks ;(


So c2 integration trapezium rule
Like in the textbook it will give you the equation so like y = 2x +3
Lines between x=1 and x=2

Use the trapezium rule with 4 strips

I don't know how to find what each value of x would be
Answer is below

So x will be 0, 0.5, 1, 1.5, 2






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should I sleep in tomorrow and feel totally refreshed for my M1 exam after lunch


OR

should I get up early and cram?

What are you doing?
Original post by Tplox
So c2 integration trapezium rule
Like in the textbook it will give you the equation so like y = 2x +3
Lines between x=1 and x=2

Use the trapezium rule with 4 strips

I don't know how to find what each value of x would be
Answer is below

So x will be 0, 0.5, 1, 1.5, 2






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Okay so:

abf(x)\int_{a}^{b} f(x) and n = number of ordinates/"strips"


To find the x values.

(b-a)/(n-1)

You mean five strips btw

So say I said:

12f(x)\int_{1}^{2} f(x) with five strips...

(2-1)/(5-1)

= 1/4 = 0.25

And you'd have

1, 1.25, 1.5, 1.75 and 2.
Reply 185
Original post by L'Evil Fish
O
You mean five strips btw


You sure? :wink:
Original post by joostan
How about:
Solve (for x) 6x=5×9x\ 6^x = 5 \times 9^x giving your answer in exact and most simplified form. :smile:


Ok you got me 🙈
I don't know...


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If I want to teach myself some modules of A level maths, what resources would you recommend? I'm considering C1 - 4, M1 - wherever and some further modules.
Reply 188
Original post by chickenonsteroids
If I want to teach myself some modules of A level maths, what resources would you recommend? I'm considering C1 - 4, M1 - wherever and some further modules.


Examsolutions.
MathsHelper.
Any textbook.
And the best till last . . .

Spoiler

Original post by joostan
You sure? :wink:


No :tongue: I cba editing

**** yeah! No more art for ever!

Finished my book!!! :biggrin: yeaaaaaaaaaah
Reply 190
Original post by L'Evil Fish
Okay so:

abf(x)\int_{a}^{b} f(x) and n = number of ordinates/"strips"


To find the x values.

(b-a)/(n-1)

You mean five strips btw

So say I said:

12f(x)\int_{1}^{2} f(x) with five strips...

(2-1)/(5-1)

= 1/4 = 0.25

And you'd have

1, 1.25, 1.5, 1.75 and 2.



My bad, I meant x=0. Not 1 sorry
But thank you, I get it now :biggrin:


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Original post by Tplox
My bad, I meant x=0. Not 1 sorry
But thank you, I get it now :biggrin:


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:smile: good!

Try this then...

13ln(x)+3\int_{1}^{3} ln(x) + 3 6 ordinates.

Just the x coordinates.
Reply 192
Original post by L'Evil Fish
No :tongue: I cba editing

**** yeah! No more art for ever!

Finished my book!!! :biggrin: yeaaaaaaaaaah

Lazy :colone: :wink:
And . . .

Spoiler

Original post by joostan
Lazy :colone: :wink:
And . . .

Spoiler



:yy:

Aaah... 41 pages in my art book done :mmm: did my final piece... I'm done... Lets see what I get :mmm:
Original post by chickenonsteroids
If I want to teach myself some modules of A level maths, what resources would you recommend? I'm considering C1 - 4, M1 - wherever and some further modules.


www.examsolutions.net/

http://www.m4ths.com/‎
(edited 10 years ago)
Original post by joostan
Examsolutions.
MathsHelper.
Any textbook.
And the best till last . . .

Spoiler






Many thanks :smile:
I am currently doing this question: the 20th term in a arithmetic sequence is -7 & the sum of the first 20 terms is 430.
How do i find 'a' & 'd'
Reply 197
Original post by annaridgway95
.


How about:

Spoiler

:smile:
Original post by Shegameister
I am currently doing this question: the 20th term in a arithmetic sequence is -7 & the sum of the first 20 terms is 430.
How do i find 'a' & 'd'


a + 19d = -7
(20/2)(a+19d) = 430

Are you sure that's right?
Reply 199
Original post by L'Evil Fish
:smile: good!

Try this then...

13ln(x)+3\int_{1}^{3} ln(x) + 3 6 ordinates.

Just the x coordinates.


1, 1 1/3, 1 2/3, 2, 2 1/3, 2 2/3, 3


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