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Parallel Vectors M1

How do I do this?

Question.JPG

I've got to (2+3lambda)i + (5-lamda)j
Reply 1
Original post by zed963
How do I do this?

Question.JPG

I've got to (2+3lambda)i + (5-lamda)j


If that is parallel to i how much j will there be?
Reply 2
Original post by TenOfThem
If that is parallel to i how much j will there be?


Wouldn't they be the same?
Reply 3
Original post by zed963
How do I do this?

Question.JPG

I've got to (2+3lambda)i + (5-lamda)j


If you imagine the vector i. Its horizontal to the x axis. So for a+λb to be parallel to i, the j component of your equation must equal 0, so a+λb is "parallel" to the x axis.
Reply 4
Original post by zed963
Wouldn't they be the same?


wouldn't what be the same
Reply 5
Original post by TenOfThem
wouldn't what be the same


The two vectors?
Reply 6
Original post by zed963
The two vectors?


Which 2 vectors?
Reply 7
Original post by TenOfThem
Which 2 vectors?


a and b.
Reply 8
I don't understand this properly, does anyone have something which explains it?
Reply 9
Original post by zed963
I don't understand this properly, does anyone have something which explains it?


If pi + qj is parallel to mi + nj

Then p = km and q= kn
Reply 10
Original post by TenOfThem
If pi + qj is parallel to mi + nj

Then p = km and q= kn


How have you got that?

if pi is parallel to mi then mi must be a factor of pi?
Original post by zed963
How have you got that?

if pi is parallel to mi then mi must be a factor of pi?


Yes but more than that

If mi + qj is parallel to ni

What do you know about q
Reply 12
Original post by TenOfThem
Yes but more than that

If mi + qj is parallel to ni

What do you know about q


q=0
Original post by zed963
q=0


Can you apply that to your original question
Reply 14
Original post by TenOfThem
Can you apply that to your original question


5-lamda=0?
Original post by zed963
5-lamda=0?


yes

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