The Student Room Group

Complex numbers

Please could some one check this
(edited 8 years ago)
Reply 1
Original post by meme12
x


Remember that (x^c)^2 = ...

And think about where this applies in your calculations.
Reply 3
Original post by meme12
Please could some one check this


squaring e is ei2θ and not what you wrote there
Reply 4
Original post by TeeEm
squaring e is ei2θ and not what you wrote there




Yes you are right , how do I get that is equal to one any idea
Reply 5
ei2θ = cos2θ + isin2θ
Reply 6
What I did so far is right if e^2iphi is equal to one
Reply 7
Original post by meme12
What I did so far is right if e^2iphi is equal to one


ei2θ = cos2θ + isin2θ
Reply 8
Tee can you send me the site address , mad for math .
Reply 9
(a+b)2=a2+2ab+b2(a+b)^2= a^2+2ab+b^2
Reply 10
Original post by meme12
Tee can you send me the site address , mad for math .


look in my profile
Reply 11
Original post by meme12
Tee can you send me the site address , mad for math .


sorry I was busy earlier

there are 2 mistakes

cosθ =1/2[ e +e-iθ]
sinθ =1/(2i)[ e - e-iθ]

and

[e ]2 is ei2θ and not what you wrote there
(edited 8 years ago)
Reply 12
It's ok , I did still didn't make difference , I have to try different way I think , I couldn't find that site in your profile .
Reply 13
Original post by meme12
It's ok , I did still didn't make difference , I have to try different way I think , I couldn't find that site in your profile .


http://madasmaths.com/
Reply 14


some very nice resources there. Many thanks for sharing.
Reply 15
Original post by dpm
some very nice resources there. Many thanks for sharing.


thank you
Reply 16
Yes I find it very useful thx.

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