Graph skethcing C1 - HELP !

y=x(x+1)(x-1)

Would the valueS of x be X=-1 , X=1 ???
Or is there more needed to be done as there is an "x" in front of the first bracket.??? Confused -.-

Reply 1

kf141998

Original post by Modesty

y=x(x+1)(x-1)

Would the valueS of x be X=-1 , X=1 ???
Or is there more needed to be done as there is an "x" in front of the first bracket.??? Confused -.-

x also equals 0

Reply 2

ubisoft

Original post by Modesty

y=x(x+1)(x-1)

Would the valueS of x be X=-1 , X=1 ???
Or is there more needed to be done as there is an "x" in front of the first bracket.??? Confused -.-

What do you mean by "values of x"?

If you mean x-intercepts, then x=0, -1, 1

Reply 3

Modesty

Original post by kf141998

x also equals 0

What do you mean?

What do i do with the "x" in front?

Reply 4

Modesty

Original post by ubisoft

What do you mean by "values of x"?

If you mean x-intercepts, then x=0, -1, 1

Sorry i meant where the graph crosses the x axis.
Btw how do you know x=0 ?
I know how to get the other intercepts but got confused of the x in front of the first bracket.

Reply 5

Andy98

Original post by Modesty

y=x(x+1)(x-1)

Would the valueS of x be X=-1 , X=1 ???
Or is there more needed to be done as there is an "x" in front of the first bracket.??? Confused -.-

It means it's a cubic graph; in this case there a three solutions. You solved

(x+1)(x-1)=0

, you needed to solve

x(x+1)(x-1)=0

Reply 6

ubisoft

Original post by Modesty

Sorry i meant where the graph crosses the x axis.
Btw how do you know x=0 ?
I know how to get the other intercepts but got confused of the x in front of the first bracket.

x on its own is the same as (x-0)

Reply 7

Andy98

Original post by Modesty

Sorry i meant where the graph crosses the x axis.
Btw how do you know x=0 ?
I know how to get the other intercepts but got confused of the x in front of the first bracket.