Question 4 is the one I need help with the book says the answer is 21% (21.2%) but I just don't know how to get that answer. I've been fine throughout the questions until this point and my text box doesn't actually give an worked example of this type of question.... It's 2:30am and I can't sleep because it's annoying me, buzzing around my head got the past 4 hours, I'm defeated by this one...: please can someone help me.... It would be greatly appreciated
Not sure where the problem lies since it's a very simple question.
Moles of N2: 0.25 therefore moles of NH3 is 0.5
0.5 * 17 = 8.5g
1.8/8.5= 0.21
Im Sorry but don't understand how moles of N are 0.25 1 mole of nitrogen is 14g I get the rest of it i think I just don't understand how nitrogen is now 0.25
Im Sorry but don't understand how moles of N are 0.25 1 mole of nitrogen is 14g I get the rest of it i think I just don't understand how nitrogen is now 0.25
Nitrogen is diatomic, as in it always comes in pairs. Therefore it's molar mass is 28 so divide the #of grams by 28 to get the moles.
Thank you so much it's so simple when someone explains it....
Haha I will remember that the hours I racked my brain I was dividing 14/7 plank So I did 7/14 to make it make sense to me = 0.5 N=14 3xH = 3 14+3=17. 0.5x17= 8.5 1.8g we made / 8.5 = 0.2110 0.211x100 = 21.1%Thank youSo to clarify without thinking of nitrogen as diatomic all for now when faced with these questions you divide the grams used/reacted (7g) by the atomic mass (14) 0.5... then add you atomic mass together in the full chemical reaction so NH3 (14+3=17) multiply them together 0.5x17 = 8.5 and what we collected is divided by 8.5 (1.8/8.5=0.211) then 0.211x100 = 21.1%Is that right