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Amount of substance chemistry

Nitration of 1.70 g of methyl benzoate (Mr = 136.0) produces methyl 3-nitrobenzoate (Mr = 181.0). The percentage yield is 65.0%
What mass, in g, of methyl 3-nitrobenzoate is produced?
A 0.830 B 1.10 C 1.47 D 2.26
(Total 1 mark)
(Total 1 mark)
To find the mass of methyl 3-nitrobenzoate produced, we need to use the percentage yield and the original mass of methyl benzoate.

First, we need to calculate the theoretical yield of methyl 3-nitrobenzoate by using the molecular weight of both compounds:

Theoretical yield = (1.70 g x 181.0 g/mol) / 136.0 g/mol = 2.26 g

Then, we can use the percentage yield to find the actual yield of methyl 3-nitrobenzoate:

Actual yield = 2.26 g x 65.0% = 1.47 g

Therefore, the answer is C) 1.47 g of methyl 3-nitrobenzoate is produced.
Reply 2
why

Original post by dulladulla
To find the mass of methyl 3-nitrobenzoate produced, we need to use the percentage yield and the original mass of methyl benzoate.

First, we need to calculate the theoretical yield of methyl 3-nitrobenzoate by using the molecular weight of both compounds:

Theoretical yield = (1.70 g x 181.0 g/mol) / 136.0 g/mol = 2.26 g

Then, we can use the percentage yield to find the actual yield of methyl 3-nitrobenzoate:

Actual yield = 2.26 g x 65.0% = 1.47 g

Therefore, the answer is C) 1.47 g of methyl 3-nitrobenzoate is produced.


why did you divide 181 by 136

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