\displaystyle [br]\begin{equation*}n! = n\underbrace{(n-1)(n-2)(n-3)\cdots (2)(1)}_{(n-1)!}\end{equation*}
\displaystyle [br]\begin{equation*} n!=n(n-1)\underbrace{(n-2)\cdots (2)(1)}_{(n-2)!} = n(n-1)(n-2)! \end{equation*}
\displaystyle [br]\begin{equation*}n! = n\underbrace{(n-1)(n-2)(n-3)\cdots (2)(1)}_{(n-1)!}\end{equation*}
\displaystyle [br]\begin{equation*} n!=n(n-1)\underbrace{(n-2)\cdots (2)(1)}_{(n-2)!} = n(n-1)(n-2)! \end{equation*}
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Did Cambridge maths students find maths and further maths a level very easy?Last reply 3 weeks ago
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Last reply 6 days ago
Did Cambridge maths students find maths and further maths a level very easy?Last reply 3 weeks ago
Edexcel A Level Mathematics Paper 2 unofficial mark scheme correct me if wrong71