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Integration by substitution

Hey,

I am revising from http://pmt.physicsandmathstutor.com/download/Maths/A-level/C4/Worksheets-Notes/OCR%20C4%20Revision%20Notes.pdf at present and did the practice integral of https://www.wolframalpha.com/input/?i=integral+from+3+to+4+2x(x%5E2-4)%5E1%2F2+dx and did it perfectly fine but it seems both aforementioned sources used the original limits instead of the new limits which makes no sense to me as I thought you had to change the limits and use those (which would give an answer of 1,040.2).

Why are they using the original limits of 3 and 4 and not 5 and 12?

Thanks.
Original post by Chichaldo
Hey,

I am revising from http://pmt.physicsandmathstutor.com/download/Maths/A-level/C4/Worksheets-Notes/OCR%20C4%20Revision%20Notes.pdf at present and did the practice integral of https://www.wolframalpha.com/input/?i=integral+from+3+to+4+2x(x%5E2-4)%5E1%2F2+dx and did it perfectly fine but it seems both aforementioned sources used the original limits instead of the new limits which makes no sense to me as I thought you had to change the limits and use those (which would give an answer of 1,040.2).

Why are they using the original limits of 3 and 4 and not 5 and 12?

Thanks.


Neither source uses the original limits (3 and 4), can explain a bit what you mean?
(edited 7 years ago)
Original post by Chichaldo
Hey,

I am revising from http://pmt.physicsandmathstutor.com/download/Maths/A-level/C4/Worksheets-Notes/OCR%20C4%20Revision%20Notes.pdf at present and did the practice integral of https://www.wolframalpha.com/input/?i=integral+from+3+to+4+2x(x%5E2-4)%5E1%2F2+dx and did it perfectly fine but it seems both aforementioned sources used the original limits instead of the new limits which makes no sense to me as I thought you had to change the limits and use those (which would give an answer of 1,040.2).

Why are they using the original limits of 3 and 4 and not 5 and 12?

Thanks.


You can use the limits of x=3x=3 and x=4x=4 if you revert your integrated function f(u)f(u) back into f(x)f(x)
Original post by _gcx
Neither source uses the original limits (3 and 4), can explain a bit what you mean?


Wolfram Alpha does by the looks of it as they I think they revert back into f(x)f(x) without showing it.
Reply 4
Original post by _gcx
Neither source uses the original limits (3 and 4), can explain a bit what you mean?


Original post by RDKGames
You can use the limits of x=3x=3 and x=4x=4 if you revert your integrated function f(u)f(u) back into f(x)f(x)


Thank you, I was being incredibly stupid and replacing u with u=x^4+1 but still using the limits in terms of u.

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