Hi,

Can anyone explain how to integrate (1-x^2)^1/2 using integration by parts as a solution I looked at is pretty confusing?

Thanks

Can anyone explain how to integrate (1-x^2)^1/2 using integration by parts as a solution I looked at is pretty confusing?

Thanks

Original post by theoneandonlyyo

Hi,

Can anyone explain how to integrate (1-x^2)^1/2 using integration by parts as a solution I looked at is pretty confusing?

Thanks

Can anyone explain how to integrate (1-x^2)^1/2 using integration by parts as a solution I looked at is pretty confusing?

Thanks

Why by parts? The usual (famous) way is with a trig substitution. Or a sketch and a bit of geometry.

(edited 6 months ago)

Original post by mqb2766

Why by parts? The usual (famous) way is with a trig substitution. Or a sketch and a bit of geometry.

Idk my lecturer wants us to know this way too

Original post by theoneandonlyyo

Idk my lecturer wants us to know this way too

You said youve got a solution? Can you upload it.

As far as I can see, you can do by parts but then you have to do the "same" trig substitution that you could do straight away. So kinda pointless.

(edited 6 months ago)

Original post by theoneandonlyyo

Idk my lecturer wants us to know this way too

Just for completeness, a quick google this morning gave

https://math.stackexchange.com/questions/533082/integral-of-sqrt1-x2-using-integration-by-parts

and the multiplication by 1, then by parts, then trig substitution/spot integral was the way I was imagining last night. Whether you argue that spotting you can get a standard integral for arcsin is not doing trig substitution is debatable. You know the solution must contain an arcsin as the sector area is based on angle but the integral limits are based on side lengths/ratios so there must be an inverse trig kicking around in there somewhere.

A bit of head scratching this morning gave another by parts by doing dots on the original integrand then by parts on the two terms but you end up doing a more complex trig substitution at the end.

(edited 6 months ago)

Original post by mqb2766

Just for completeness, a quick google this morning gave

https://math.stackexchange.com/questions/533082/integral-of-sqrt1-x2-using-integration-by-parts

and the multiplication by 1, then by parts, then trig substitution/spot integral was the way I was imagining last night. Whether you argue that spotting you can get a standard integral for arcsin is not doing trig substitution is debatable. You know the solution must contain an arcsin as the sector area is based on angle but the integral limits are based on side lengths/ratios so there must be an inverse trig kicking around in there somewhere.

A bit of head scratching this morning gave another by parts by doing dots on the original integrand then by parts on the two terms but you end up doing a more complex trig substitution at the end.

https://math.stackexchange.com/questions/533082/integral-of-sqrt1-x2-using-integration-by-parts

and the multiplication by 1, then by parts, then trig substitution/spot integral was the way I was imagining last night. Whether you argue that spotting you can get a standard integral for arcsin is not doing trig substitution is debatable. You know the solution must contain an arcsin as the sector area is based on angle but the integral limits are based on side lengths/ratios so there must be an inverse trig kicking around in there somewhere.

A bit of head scratching this morning gave another by parts by doing dots on the original integrand then by parts on the two terms but you end up doing a more complex trig substitution at the end.

Thank you so much for this solution! I am still very confused tho haha but I will just stick to the trig substitution method. It won't let me upload the solution too:/

Original post by theoneandonlyyo

Thank you so much for this solution! I am still very confused tho haha but I will just stick to the trig substitution method. It won't let me upload the solution too:/

WHat are you confused about (in the stackexchange solution)?

Original post by mqb2766

WHat are you confused about (in the stackexchange solution)?

The I bit

Original post by theoneandonlyyo

The I bit

Would help to be a bit more specific, but if youre referring to the integral of

-x^2/sqrt(1-x^2)

then adding zero (1-1) to the numerator gives two integrals

(1-x^2)/sqrt(1-x^2)

and

-1/sqrt(1-x^2)

The latter is the usual arcsin() integral and the former is the original integral, so I. So you can take it over to the left hand side and divide by 2 to get the result.

If you cant see it, write up (and post) what you do understand.

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