Find probability that number of 2.4<T<2.6 is at least 15
Table cloths made with normal distribution
T ~ N(2.5 , 0.1298^2)
Table cloth can be sold if 2.4<T<2.6. A sample of 20 table cloths is taken, how many can be sold?
________
I know P(2.4<T<2.6) = 0.5589
So the expected number of table cloths is 11.178.
But how do I find the probability that it is greater?
T ~ N(2.5 , 0.1298^2)
Table cloth can be sold if 2.4<T<2.6. A sample of 20 table cloths is taken, how many can be sold?
________
I know P(2.4<T<2.6) = 0.5589
So the expected number of table cloths is 11.178.
But how do I find the probability that it is greater?
Original post by Retsek
Table cloths made with normal distribution
T ~ N(2.5 , 0.1298^2)
Table cloth can be sold if 2.4<T<2.6. A sample of 20 table cloths is taken, how many can be sold?
________
I know P(2.4<T<2.6) = 0.5589
So the expected number of table cloths is 11.178.
But how do I find the probability that it is greater?
T ~ N(2.5 , 0.1298^2)
Table cloth can be sold if 2.4<T<2.6. A sample of 20 table cloths is taken, how many can be sold?
________
I know P(2.4<T<2.6) = 0.5589
So the expected number of table cloths is 11.178.
But how do I find the probability that it is greater?
Given that each table cloth is subject to a pass/fail test and that there is a known number of tests, you could explore the probability that a particular number, or range of numbers, of table cloths can be sold by looking at the binomial distribution B(20, 0.5589).
Probability that what is greater? If you probability is correct then 11.178 is right, you dont need to do anything else beside giving it to the nearest whole number.
Original post by Radioactivedecay
Probability that what is greater? If you probability is correct then 11.178 is right, you dont need to do anything else beside giving it to the nearest whole number.
Probability that out of the 20, 15 or more are of a suitable width.
Original post by old_engineer
Given that each table cloth is subject to a pass/fail test and that there is a known number of tests, you could explore the probability that a particular number, or range of numbers, of table cloths can be sold by looking at the binomial distribution B(20, 0.5589).
Brilliant fab!
Original post by Retsek
Probability that out of the 20, 15 or more are of a suitable width.
If that is part of the question, you didnt write it in your initial post. Nonetheless, are you familiar with the binomial distribution?
Original post by Radioactivedecay
If that is part of the question, you didnt write it in your initial post. Nonetheless, are you familiar with the binomial distribution?
My bad you're right I should've proof-read before posting, yeah I think I know how to do it now:
T ~ B(20 , 0.5589)
P(T>=15)
1 - P(T=<14)
1 - 0.9352 = 0.0648
Is my value for P(T=<14) correct? I'm not sure I put it in my calculator properly
Original post by Retsek
My bad you're right I should've proof-read before posting, yeah I think I know how to do it now:
T ~ B(20 , 0.5589)
P(T>=15)
1 - P(T=<14)
1 - 0.9352 = 0.0648
Is my value for P(T=<14) correct? I'm not sure I put it in my calculator properly
T ~ B(20 , 0.5589)
P(T>=15)
1 - P(T=<14)
1 - 0.9352 = 0.0648
Is my value for P(T=<14) correct? I'm not sure I put it in my calculator properly
How did you find a cumulative probabilty using the calculator? To find P(X>=15) you have to add up the separate prbabilites from 15 to 20.
Original post by Retsek
My bad you're right I should've proof-read before posting, yeah I think I know how to do it now:
T ~ B(20 , 0.5589)
P(T>=15)
1 - P(T=<14)
1 - 0.9352 = 0.0648
Is my value for P(T=<14) correct? I'm not sure I put it in my calculator properly
T ~ B(20 , 0.5589)
P(T>=15)
1 - P(T=<14)
1 - 0.9352 = 0.0648
Is my value for P(T=<14) correct? I'm not sure I put it in my calculator properly
Looks good to me.
Original post by Radioactivedecay
How did you find a cumulative probabilty using the calculator? To find P(X>=15) you have to add up the separate prbabilites from 15 to 20.
I've got a fancy calculator that can do distributions and stuff, put in:
x = 14
N = 20
p = 0.5589
To get P(X=<14)
Original post by Retsek
I've got a fancy calculator that can do distributions and stuff, put in:
x = 14
N = 20
p = 0.5589
To get P(X=<14)
x = 14
N = 20
p = 0.5589
To get P(X=<14)
Nice, is it the fx9860gii by any chance?
Original post by Radioactivedecay
Nice, is it the fx9860gii by any chance?
Nope, it's a Casio fx-991EX classwiz
Just the one I was told to get for my further maths a-level ¯\_(ツ)_/¯
Original post by Retsek
Nope, it's a Casio fx-991EX classwiz
Just the one I was told to get for my further maths a-level ¯\_(ツ)_/¯
Just the one I was told to get for my further maths a-level ¯\_(ツ)_/¯
Original post by Retsek
Nope, it's a Casio fx-991EX classwiz
Just the one I was told to get for my further maths a-level ¯\_(ツ)_/¯
Just the one I was told to get for my further maths a-level ¯\_(ツ)_/¯
Same
feel sorry when I see also those tables in back of textbook / remembering writing out binomial probabilities.Original post by Canary84
Same feel sorry when I see also those tables in back of textbook / remembering writing out binomial probabilities.
feel sorry when I see also those tables in back of textbook / remembering writing out binomial probabilities.Is that calculator allowed in the exam?
Original post by dhruvap
Is that calculator allowed in the exam?
Yeah it's the one recommended to us by the exam board and is sold in our maths department no need to worry 😅
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