Original post by CalliciousOkay. Here's an idea of the train of thinking; if it doesn't help, please say and I can elucidate the issue better... either ways, here goes:
From the first point where the mesons pass, you start a clock. By the end, in your frame, you record a time, and for that set velocity the mesons have, a distance, and so in that time you see a fraction of them disappear.
The mesons are at relativistic speeds, and so, in effect, time will be slower as you observe them with respect to yours: you can derive this quite simply w/ a light clock and pythagoras for many examples, alongside other derivations. It's a simple way of saying it, but you will just observe their clock moving slower than yours. So, for 3/4 of them to disappear, there must have been two half lives past: Is it in your frame, or their frame? If their time is moving slower than ours for example, then the half life we record will be longer for them, after all their time is slowed, and in effect their decay is slowed, correct?
SO! That's where this question goes. You need to apply a transformation for the half lives they pass. 3/4 are gone, so 0.25 remains, 25% of them, and so two half lives have passed. Not in your frame, but in theirs, in their frame 75% are gone, and so we observe that 75% have poofed.
Do you know a transformation that can do this?