The Student Room Group
Reply 1
Write it as lnx+1x\ln \dfrac{x+1}{x} and use the laws of logs to break it down a little, then you can look for stationary points and what happens as x|x| \to \infty.

Spoiler

Well there's gonna be vertical asymptotes at x=0 and when x=-1. Will there be any horizontal asymptotes? Consider what happens when -1 < x < 0 and when x < -1 and when x > 0.

You don't really need to rewrite it in order to draw it but like nuodai said, look at the gradient.
Reply 3
thanks
i got it

the question i had was to prove

(ln (x) )/x > ln(1 + 1/x)

for x>2

i tried to draw the graphs and compare since i couldnt quite get it with induction
could you guys give me a hint of how i should do it
thanks again :wink:
The only way I could think of would be to draw each graph (it's not that hard) and then algebraically find their intersection point.
Reply 5
thanks, could you show me how you would find ther intersection point

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