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Need help with Integration

Can anyone help me integrate this equation?

⁴∫((⅛)x^3/2 - 4/x) dx
¹
Reply 1
Original post by MWorldwide19
Can anyone help me integrate this equation?

⁴∫((⅛)x^3/2 - 4/x) dx
¹
What are you stuck with? Both terms should be fairly standard integrals.
Original post by mqb2766
What are you stuck with? Both terms should be fairly standard integrals.
^^ and what have you tried so far ?
Original post by MWorldwide19
Can anyone help me integrate this equation?

⁴∫((⅛)x^3/2 - 4/x) dx
¹
Also, let's just confirm we're reading this right - is this what you're trying to integrate?

1418x3/24xdx\displaystyle \int_1^4 \frac{1}{8}x^{3/2} - \frac{4}{x} \,dx

If not, please clarify exactly what you're doing - if in doubt, use more brackets.
(edited 1 month ago)
Original post by miss_nia
^^ and what have you tried so far ?


I've integrated the (1/8)x^(3/2) to get 31/20. I'm just stuck on integrating the 4/x because I get (-4ln|4| +4ln|1|) yet the answer to that should get me like (-8ln(2)) I'm pretty sure and I don't really know how I get there
Original post by mqb2766
Original post by MWorldwide19
Can anyone help me integrate this equation?

⁴∫((⅛)x^3/2 - 4/x) dx
¹
What are you stuck with? Both terms should be fairly standard integrals.


I think I'm just getting myself confused with arithmetic honestly
Original post by MWorldwide19
I've integrated the (1/8)x^(3/2) to get 31/20. I'm just stuck on integrating the 4/x because I get (-4ln|4| +4ln|1|) yet the answer to that should get me like (-8ln(2)) I'm pretty sure and I don't really know how I get there
Ln ab = (ln a)+(ln b). This should tell you how ln 1 and ln 4 can be written in terms of ln 2...

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