Can anyone help me integrate this equation?

⁴∫((⅛)x^3/2 - 4/x) dx

¹

⁴∫((⅛)x^3/2 - 4/x) dx

¹

Original post by MWorldwide19

Can anyone help me integrate this equation?

⁴∫((⅛)x^3/2 - 4/x) dx

¹

⁴∫((⅛)x^3/2 - 4/x) dx

¹

Original post by mqb2766

What are you stuck with? Both terms should be fairly standard integrals.

Original post by MWorldwide19

Can anyone help me integrate this equation?

⁴∫((⅛)x^3/2 - 4/x) dx

¹

⁴∫((⅛)x^3/2 - 4/x) dx

¹

$\displaystyle \int_1^4 \frac{1}{8}x^{3/2} - \frac{4}{x} \,dx$

If not, please clarify exactly what you're doing - if in doubt, use more brackets.

(edited 1 month ago)

Original post by miss_nia

^^ and what have you tried so far ?

I've integrated the (1/8)x^(3/2) to get 31/20. I'm just stuck on integrating the 4/x because I get (-4ln|4| +4ln|1|) yet the answer to that should get me like (-8ln(2)) I'm pretty sure and I don't really know how I get there

Original post by mqb2766What are you stuck with? Both terms should be fairly standard integrals.

Original post by MWorldwide19

Can anyone help me integrate this equation?

⁴∫((⅛)x^3/2 - 4/x) dx

¹

⁴∫((⅛)x^3/2 - 4/x) dx

¹

I think I'm just getting myself confused with arithmetic honestly

Original post by MWorldwide19

I've integrated the (1/8)x^(3/2) to get 31/20. I'm just stuck on integrating the 4/x because I get (-4ln|4| +4ln|1|) yet the answer to that should get me like (-8ln(2)) I'm pretty sure and I don't really know how I get there

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