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Proof that the squareroot of -i is 17.
squareroot of -i = (-i)^1/2 = 1 + (-i)^1/2 - 1 != 2, since 2^2 = 4 != -i.
Now 2 != 17
=> (-i)^1/2 = 17.
Now 2 != 17
=> (-i)^1/2 = 17.
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fishpaste
Yes.
lol.
I never considered myself fallible.
fishpaste
squareroot of -i = (-i)^1/2 = 1 + (-i)^1/2 - 1 != 2, since 2^2 = 4 != -i.
Now 2 != 17
=> (-i)^1/2 = 17.
Now 2 != 17
=> (-i)^1/2 = 17.
Maybe I'm being stupid, but does 2! not mean 2 factorial i.e. 2*1 and therefore just 2? To be honest I lost you after squareroot (-i) =(-i)^1/2
hitchhiker_13
Maybe I'm being stupid, but does 2! not mean 2 factorial i.e. 2*1 and therefore just 2? To be honest I lost you after squareroot (-i) =(-i)^1/2
Ok it's not just me being stupid, you're taking the piss. Phew! I didn't want to say anything in case I was just an idiot.
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