The Student Room Group

Stuck on this C1 Question

Solved =)
(edited 13 years ago)
Its completing the square. Factorise the whole expression to get the 2 out
Reply 2
Original post by WildBerry


I'm not sure how to do this question :s-smilie:


Multiply out the bracket on the right hand side and equate the coefficients.

EDIT: What's with the neg rep? It's a perfectly valid method.
(edited 13 years ago)
2x212x+p=q(xr)2+102x^{2}-12x+p=q(x-r)^{2}+10
So now remove the 2 and put it as a factor
2(x26x+p/2)2(x^{2}-6x+p/2)
Then do complete the square
2((x3)29+p/2)2((x-3)^{2}-9+p/2)
Then multiply the -9 and P/2 by 2 to take it out of the bracket
2(x3)218+P2(x-3)^{2}-18+P
now, 10 must = -18+P
so P=28
q=2
and
r=3
Hope it helps :smile:
Original post by thecookiem0nster
2x212x+p=q(xr)2+102x^{2}-12x+p=q(x-r)^{2}+10
So now remove the 2 and put it as a factor
2(x26x+p/2)2(x^{2}-6x+p/2)
Then do complete the square
2((x3)29+p/2)2((x-3)^{2}-9+p/2)
Then multiply the -9 and P/2 by 2 to take it out of the bracket
2(x3)218+P2(x-3)^{2}-18+P
now, 10 must = -18+P
so P=28
q=2
and
r=3
Hope it helps :smile:


This.
Reply 5
Thanks alot for the help =)

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