OCR MEI C2 MAY 18th

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Original post by King of the Jungle

How could the y intercept be when y coordinate was 1 o r something

The x-coord was 1, the y-coord was 5, I think? I thought the same thing at first and then realised I was looking at x, not y. So the intercept definitely is 2.

Reply 441

sarah:))

guys yu know on the trapezium rule question... i realised i used the x-values as my mid y-values e.g for (2x(y2+y3+y4+y5...) would i get 0 marks out of 4 for this mistake?
i can't believe i did this, soo stupid!!

(edited 11 years ago)

Reply 442

564767

First one was a transformation of a(fx) so you times the y co-ord by 3.
The second one was of f(ax) so times the x co-ord by a scale factor of 1/4.

I think for the first the co-ord was 3,9.
The second was 1.5 or something

Reply 443

Neuro Alex

I thought I did fairly well in this exam, not going to go through this thread because it has a habit of depressing me lol!

Didn't have time to check my answers so hope I didn't make many mistakes! - I lost a few marks on the log question and only got 2/4 solutions for the 2sintheta one.

Hoping for around 90 % UMS if the grade boundaries play ball, I reckon an A could be around 53-58.

Reply 444

WizKidd

Original post by pixxie

It's not the end of the world! :smile:

There's quite a few things I did wrong, like the logs question, but the end of the day you can always resit if you want - and you'll have probably done better than you think anyway.
You get method marks for eeeeasy things, and you can still drop about 14 marks to get an A :O (dunno what you're hoping for but you know what I mean...)
plus the UMS marks change things.

Basically, it's not really worth stressing over :biggrin:

Aww thanks :smile:

Well I was hoping for an A but I'm inevitably going to fail stats so I wanted c1 and c2 to make up for that. Onto the next one I guess!

Reply 445

jonny7bell

Original post by ss2012

That's what I thought? And I sub'ed in both in the later q :s-smilie:

This was posted from The Student Room's Android App on my GT-I9100

It is. But the model doesnt give a fully accurate representation of the graph, so if you subbed x=0.2 into the model then it equals slightly less than 0.6 which is what it is supposed too.

Reply 446

sarah:))

guys yu know on the trapezium rule question... i realised i used the x-values as my mid y-values e.g for (2x(y2+y3+y4+y5...) would i get 0 marks out of 4 for this mistake?

Reply 447

ArsenalWenger

For the sin equation, I stupidly put two of my solutions in degrees instead of radians, How many marks would I lose for this?

Also for part i of the last question, I had the two formulas but couldn't rearrange to get the answers, but got the answers using trial and improvement, How many marks would I lose for this?

Reply 448

mattparker

Original post by ArsenalWenger

Also for part i of the last question, I had the two formulas but couldn't rearrange to get the answers, but got the answers using trial and improvement, How many marks would I lose for this?

I did this aswell!

Reply 449

King of the Jungle

Original post by Deceptively

The x-coord was 1, the y-coord was 5, I think? I thought the same thing at first and then realised I was looking at x, not y. So the intercept definitely is 2.

its good i put that down i was regretting so much but i did put 2 =) thanks for relieving me of that regret

Reply 450

pixxie

Original post by WizKidd

Aww thanks :smile:

Well I was hoping for an A but I'm inevitably going to fail stats so I wanted c1 and c2 to make up for that. Onto the next one I guess!

thats not the attitude :O & i bet you won't fail it :wink:

good luck though :smile:

Reply 451

AspiringGenius

Original post by Deceptively

I'm afraid so, from what I can tell... Since the 4 is inside the function, it's a stretch s.f. 1/4 in the x-direction - i.e. the x-coordinate changes but the y-coord doesn't, as the graph is "squashed" inwards but not "flattened". So it should be (3/2, 3) (is that what the y-coord was? I can't remember, but basically the y-coord remains as it was in the question).

Ahh well so i know I lost five marks (those two and the one at the end). I might have picked up a mark for working but i can't remember if I did anything there.

in all fairness I got a D in the mock so I'm glad I'm not thinking I didn't get half the paper now. here's hoping for 90%+ (for A* prediction!)

Reply 452

sarah:))

for the trapezium rule question... i realised i used the x-values as my mid y-values e.g for (2x(y2+y3+y4+y5...) would i get 0 marks out of 4 for this mistake? :s-smilie:

(edited 11 years ago)

Reply 453

Deceptively

Original post by sarah:))

for the trapezium rule question... i realised i used the x-values as my mid y-values e.g for (2x(y2+y3+y4+y5...) would i get 0 marks out of 4 for this mistake? :s-smilie:

No need to post this so many times, Sarah - once would do! :smile:

I'm afraid it's unlikely you'd get any marks - past mark schemes for similar questions make no mention of awarding marks for an attempt at using the formula... quite annoying as it's probably a mistake several people have made... the only mention of awarding marks is M2 (out of M3+A1) for one slip or M1 for two slips. Sorry.

Reply 454

sarah:))

Original post by Deceptively

No need to post this so many times, Sarah - once would do! :smile:

thanks.. i just wanted a reply :smile:

and i can't believe i made such a stupid mistake.. just hope i can still get an A :s-smilie:

Reply 455

alex7892

What do people expect the grade boundaries will be for an A?

Reply 456

ss2012

anyone has the jan 2012 stats 1 paper marking scheme? REALLY NEED IT!

Reply 457

ss2012

anyone has the S1 2012 marking scheme?

Reply 458

thepastpaper

Original post by thepastpaper

iv lost about 13 marks and still counting :/ that log questions i didnt have a clue :frown:

and the last part of question 9 and 11. hopefully the grade boundaries are low.

june 09: 51
june 10: 49
june 11: 53
june 12: ?? what do you think... lets see how people have found it and work out an estimate later :smile:

52/72 for an A?