Redox question
http://filestore.aqa.org.uk/subjects/AQA-CHEM5-W-QP-JUN10.PDF
Q7d)
1. I found mass of original Fe2+ (55.8/277.90) = 2.01g
2. I found moles of Cr2O7 2- (23.7x10^-3x0.01)=2.37x10^-4 moles
3. I found the overall equation by combining 2 half equation, Cr2O7 2- : 6Fe2+
4. 6 x 2.37x10^-4 x 10 = moles of Fe2+
Is this the moles of Fe2+ that reacts?
So that if i turn this into mass and take it from 2.01 i would get the Fe2+ left?
Q7d)
1. I found mass of original Fe2+ (55.8/277.90) = 2.01g
2. I found moles of Cr2O7 2- (23.7x10^-3x0.01)=2.37x10^-4 moles
3. I found the overall equation by combining 2 half equation, Cr2O7 2- : 6Fe2+
4. 6 x 2.37x10^-4 x 10 = moles of Fe2+
Is this the moles of Fe2+ that reacts?
So that if i turn this into mass and take it from 2.01 i would get the Fe2+ left?
Original post by Borek
You are ignoring fact you titrated 25 mL, not the whole solution.
I multiplied by 10 already for 250ml solution, hold on i will draw a diagram. Its just an understanding issue.
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