help with trig identites

how can you simplify the following?
sinx/cosx + cosx/sinx

tanx/1-sec^2x

1/tanx +cotx

help asap please

how can you simplify the following?
sinx/cosx + cosx/sinx

(sinx/cosx) + (cosx/sinx)

take L.C.M

( sin^2 x + cos^2 x ) / (sinx cosx)

Now apply trigonometric identities

sin^2(u) + cos^2(u) = 1

2 sin(u) cos(u) = sin(2u) :smile:

Reply 2

Purple27

Original post by Tutorsos

(sinx/cosx) + (cosx/sinx)

take L.C.M

( sin^2 x + cos^2 x ) / (sinx cosx)

Now apply trigonometric identities

sin^2(u) + cos^2(u) = 1

2 sin(u) cos(u) = sin(2u) :smile:

thank you for helping but i can't put it in as fraction :frown:

rand.JPG43.6KB

Reply 3

Tutorsos

Original post by Purple27

thank you for helping but i can't put it in as fraction :frown:

Apply fallowing trigonometric identities

1) apply second identity for numerator

apply third identity for denominator

2) hint given in the above post

3) apply third identity for denominator

show your work ... :smile:

Reply 4

davros

Original post by Purple27

thank you for helping but i can't put it in as fraction :frown:

You can put it as a fraction - the numerator simplifies using the identity given and then you just need to fiddle about with the denominator,

For the others you need to show some working so we can see where you are stuck!!