# help with trig identites

#1
how can you simplify the following?
sinx/cosx + cosx/sinx

tanx/1-sec^2x

1/tanx +cotx

0
7 years ago
#2
(Original post by Purple27)
how can you simplify the following?
sinx/cosx + cosx/sinx
(sinx/cosx) + (cosx/sinx)

take L.C.M

( sin^2 x + cos^2 x ) / (sinx cosx)

Now apply trigonometric identities

sin^2(u) + cos^2(u) = 1

2 sin(u) cos(u) = sin(2u)
0
#3
(Original post by Tutorsos)
(sinx/cosx) + (cosx/sinx)

take L.C.M

( sin^2 x + cos^2 x ) / (sinx cosx)

Now apply trigonometric identities

sin^2(u) + cos^2(u) = 1

2 sin(u) cos(u) = sin(2u)
thank you for helping but i can't put it in as fraction
0
7 years ago
#4
(Original post by Purple27)
thank you for helping but i can't put it in as fraction
Apply fallowing trigonometric identities

1) apply second identity for numerator

apply third identity for denominator

2) hint given in the above post

3) apply third identity for denominator

0
7 years ago
#5
(Original post by Purple27)
thank you for helping but i can't put it in as fraction
You can put it as a fraction - the numerator simplifies using the identity given and then you just need to fiddle about with the denominator,

For the others you need to show some working so we can see where you are stuck!!
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