Complex numbers help
Can anybody please help me with this question I am really confused.
It is given that z = x+iy
Solve the equation (Z+i)* = 2iz+1
in the form a+bi
Where (z+i)* denotes the complex conjugate of (z+i)
Many thanks to anyone who can help
It is given that z = x+iy
Solve the equation (Z+i)* = 2iz+1
in the form a+bi
Where (z+i)* denotes the complex conjugate of (z+i)
Many thanks to anyone who can help
Original post by JxxxjoexxxJ
Can anybody please help me with this question I am really confused.
It is given that z = x+iy
Solve the equation (Z+i)* = 2iz+1
in the form a+bi
Where (z+i)* denotes the complex conjugate of (z+i)
Many thanks to anyone who can help
It is given that z = x+iy
Solve the equation (Z+i)* = 2iz+1
in the form a+bi
Where (z+i)* denotes the complex conjugate of (z+i)
Many thanks to anyone who can help
z = x + yi
z* = x - yi
Therefore, (z+i)* = ...
Therefore, 2iz + 1 = ...
Hint: substitute
Note that the complex conjugate is simply the complex number with negated imaginary part
i.e. you flip the point in the real axis of the argand diagram.
Just for reference!
i.e. you flip the point in the real axis of the argand diagram.
Just for reference!
So does the (z+i)* Become x+iy-i, or x-iy+i or x-iy-i?
Original post by JxxxjoexxxJ
So does the (z+i)* Become x+iy-i, or x-iy+i or x-iy-i?
z = x+iy
z+i = x+(y+1)i
(z+i)* = x-(y+1)i
Original post by JxxxjoexxxJ
So does the (z+i)* Become x+iy-i, or x-iy+i or x-iy-i?
Well z + i = x + iy + i = x + i(y + 1)
so what does the rule for conjugation do to this?
Oh ok I understand now thank you everyone for your help! 
Original post by davros
Well z + i = x + iy + i = x + i(y + 1)
so what does the rule for conjugation do to this?
so what does the rule for conjugation do to this?
I just recently started complex numbers, why does z+i equals that? where did the y+1 come from?
Original post by kkboyk
I just recently started complex numbers, why does z+i equals that? where did the y+1 come from?
not sure what you are struggling with
z also has yi and then you add another i so that makes (y+1)i
Original post by kkboyk
I just recently started complex numbers, why does z+i equals that? where did the y+1 come from?
z = x + iy
z + i = x + iy + i
Which is the same as x + (y+1)i
Original post by L'Evil Fish
z = x + iy
z + i = x + iy + i
Which is the same as x + (y+1)i
z + i = x + iy + i
Which is the same as x + (y+1)i
Oh right! Forgot that z = x +iy is exactly the same as z = a + bi
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