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AQA A2 Mathematics MPC3 Core 3 - Friday 5th June 2015 [Exam Discussion Thread]

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Jan12 q6b - horrible substitution one, I managed to get so far as cosx but cannot get the solutions?

x = cosecθ

Rearrange for θ: θ = sin-1(1/x)
Input values for x in, and get values for θ --- these are the new limits of the integral...

so cos(0.524) - cos (0.785) = 0.159 to 3sf

Reply 1181

CD223

Original post by SpaceXFan

x = cosecθ

Rearrange for θ: θ = sin-1(1/x)
Input values for x in, and get values for θ --- these are the new limits of the integral...

so cos(0.524) - cos (0.785) = 0.159 to 3sf

Would you lose marks for working in decimal?

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Reply 1182

Lau14

Original post by CD223

Well tbh, I'll note down all my answers and if no one has already posted an unofficial MS, I'll add it to the first post of this thread/make a new thread :smile:

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Unfortunately I expect we'll have to clear our calculators between exams, so I'll have to see how much C3 I can remember!

Reply 1183

Lau14

Original post by CD223

Would you lose marks for working in decimal?

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You may do, as I think we are expected to know exact values for common trig - they do often ask for the answer to be exact as well.

Reply 1184

SpaceXFan

Original post by CD223

Would you lose marks for working in decimal?

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Well the mark scheme gives it in decimal... so no. Usually, however, they ask for exact value.

Reply 1185

ankitaa123

Original post by CD223

Erm, not that I can think of 👀 Product is for multiplication of two functions, chain is where you have a function inside another one. Can't really think of a way of spotting it beyond that 😁

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I know who you are now! Thank youu so much, just had a blank moment, stressing out :smile:

good luck

Reply 1186

matthew6665

Original post by 2014_GCSE

Hardest past paper? Done the 2010 set because some people said those were hard. Any others?

JANUARY 2012. Quite easy up to question 6. Then its HELL

Reply 1187

CD223

Original post by Lau14

Unfortunately I expect we'll have to clear our calculators between exams, so I'll have to see how much C3 I can remember!

Oh right! I should probably learn how to reset my calculator before tomorrow...

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Reply 1188

CD223

Original post by ankitaa123

I know who you are now! Thank youu so much, just had a blank moment, stressing out :smile:

good luck

Hahahaha, hello :wink:

good luck for tomorrow AK :smile:

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Reply 1189

Lau14

Original post by CD223

Oh right! I should probably learn how to reset my calculator before tomorrow...

Posted from TSR Mobile

Our invigilators tend to talk everyone through it (mine's easy - you take the back off, put it back on and press clear :tongue:

)... I'd think we have to do it between exams anyway, we do at the start.

Reply 1190

ankitaa123

Original post by CD223

Hahahaha, hello :wink:

good luck for tomorrow AK :smile:

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Awks when I ask a stupid question and Chris finds it hahahaha

Reply 1191

UOE15

Original post by SpaceXFan

x = cosecθ

Rearrange for θ: θ = sin-1(1/x)
Input values for x in, and get values for θ --- these are the new limits of the integral...

so cos(0.524) - cos (0.785) = 0.159 to 3sf

Original post by CD223

Have you changed the limits correctly?

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My teacher taught me to integrate then change back to what you substituted then use original limits if that make sense but that doesn't work in this case hence I was confused, but I have worked it through now thankfully, thank you!

Reply 1192

CD223

Original post by Lau14

Our invigilators tend to talk everyone through it (mine's easy - you take the back off, put it back on and press clear :tongue:

)... I'd think we have to do it between exams anyway, we do at the start.

Oh that's good! Just found out how to do mine :tongue:

Hopefully they don't make me clear it afterwards. That's my only way of remembering the majority of answers haha!

Original post by ankitaa123

Awks when I ask a stupid question and Chris finds it hahahaha

Hahahah!

No such thing as a stupid question! Really hoping tomorrow is a kind paper :s-smilie:

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Reply 1193

tiffanyyyyyyy

FUNCTIONS!! I have a question about them:

when finding the inverse of a function, sometimes the answer ends up as +/- because there is a root. However, from looking at mark schemes, it tells you to ignore one sign or the other? when would you do so cause i'm confused??
For example, in the Jun 14 paper it tells you to ignore the negative. In the january 13, it tells you to ignore positive?
why?? thanks

Reply 1194

CD223