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Basic M1 Vectors Question



I can't seem to understand what's going on in the example above! Can someone please explain to me what is going on and why?
Original post by creativebuzz
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I can't seem to understand what's going on in the example above! Can someone please explain to me what is going on and why?


speed is 15, so you need a velocity vector with a magnitude of 15

the direction of your vector has to be parallel to 3i-4j

so you need a multiple of 3i-4j that has a magnitude of 15



I assume that you know the magnitude of 3i-4j is 5

so you multiply it by 3 to get a magnitude of 15



once you have your velocity vector, you do that twice because you have 2 seconds
(edited 9 years ago)
you know the direction of the velocity & its magnitude, so you can work out the correct components of velocity.
Original post by TenOfThem
speed is 15, so you need a velocity vector with a magnitude of 15

the direction of your vector has to be parallel to 3i-4j

so you need a multiple of 3i-4j that has a magnitude of 15



I assume that you know the magnitude of 3i-4j is 5

so you multiply it by 3 to get a magnitude of 15



once you have your velocity vector, you do that twice because you have 2 seconds

Brilliant explanation, I now understand it! Thank you :smile:
Original post by the bear
you know the direction of the velocity & its magnitude, so you can work out the correct components of velocity.


thanks!

by the way, would you mind seeing where I went wrong in my working out? I found in part a of the question so I thought I could use that v and substitute it into the equation r = r0 + vt but I didn't get the right answer(I'm referring to part B)!

Original post by creativebuzz
thanks!

by the way, would you mind seeing where I went wrong in my working out? I found in part a of the question so I thought I could use that v and substitute it into the equation r = r0 + vt but I didn't get the right answer(I'm referring to part B)!



in red is for zero acceleration... you need

r = ro + ut + 0.5at2
Original post by the bear
in red is for zero acceleration... you need

r = ro + ut + 0.5at2


Oh okay, so if the particle is accelerating I must use "long formula" but if it isn't accelerating then I should use r=r0 + Vt?
Original post by creativebuzz
Oh okay, so if the particle is accelerating I must use "long formula" but if it isn't accelerating then I should use r=r0 + Vt?


yes... it is exactly the same formula but with a = 0
Original post by the bear
yes... it is exactly the same formula but with a = 0


Thank you soo much, you explained that perfectly! 😄😊😀😃
Original post by creativebuzz
Thank you soo much, you explained that perfectly! 😄😊😀😃


no worries blud
Original post by the bear
no worries blud







Do do you mind spotting where I went wrong in question 5, part a? 😨
Original post by creativebuzz




Do do you mind spotting where I went wrong in question 5, part a? 😨


your triangle of forces... the big angle on the left should be 90 degrees, the top one 40...
Original post by the bear
your triangle of forces... the big angle on the left should be 90 degrees, the top one 40...


How did you know where each angle should go in the triangle of force?
it is like making a jigsaw from the 3 lines on the diagram. you move them around, do not change the direction until they fit nose to tail. then the angles in the triangle can be read off from the angles in the original diagram.
Original post by the bear
it is like making a jigsaw from the 3 lines on the diagram. you move them around, do not change the direction until they fit nose to tail. then the angles in the triangle can be read off from the angles in the original diagram.


Sorry, I've only just seen this. But I understand the whole jigsaw and creating the actual diagram, I just don't know how the angles match up? (e.g. alternate angles etc)

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