Original post by sefulK
Do you know how to work the equation of the tangent line at Q?
Yes it's
y = xt - 2t^2
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y = xt - 2t^2
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Original post by sefulK
Hmm. I think you want an equation without t in it. Just to check, how did you get that equation?
Then get the equation for the other tangent then you can do the question
Like that, I got the equation without t in it but I presumed it won't help. How do you get the equation of either tangent?
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I've managed to get the x coord, but getting the wrong y coord. x coord is 2(t1 + t2)
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Original post by sefulK
I've managed to get the x coord, but getting the wrong y coord. x coord is 2(t1 + t2)
Posted from TSR Mobile
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So, your x-coordinate is , and if you sub that back into either tangent equation, you should get the y-coordinate as
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