Hi. I cant solve this problem.
Find d if the line passing through (−2,−1) and (3,2) is perpendicular to the line
A (−2,−1) and B(3,2) , line dx +2y−3=0
(gradient AB)*(gradient of the line) = -1
Could you please explain how to do this?
Thank you so much!
Please help with solving Trigonometry Watch
- Thread Starter
- 05-04-2016 03:28
- 05-04-2016 13:40
A (−2,−1) and B(3,2)
-2 = x1
-1 = y1
To find M, the gradient, you use:
=3/5 (you got M using the values from the given coordinates)
Then to find the equation, after finding M, you use this formula:
The perpendicular would be -5/3x(so d would be [-5/3])(Multiply by -1 and then flip the fraction find the reciprocal))
To finally check multiply the two gradients together, it should as the question said give you -1.3/5*-5/3 = -1, so it’s correct