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Trig problems need help

How can I shows that these two expressions underlined are the same ? 1475087049668952323006.jpg thanks
Reply 1
Original post by coconut64
How can I shows that these two expressions underlined are the same ? 1475087049668952323006.jpg thanks


You seem to have some confusion about fractions here...

Step 1) Note 1abc=1a×1b×1c \displaystyle \frac{1}{abc} = \frac{1}{a} \times \frac{1}{b} \times \frac{1}{c}

Step 2) What's the definition of sec(x) \displaystyle \sec(x) ? What about cot(x) \displaystyle \cot(x) ?

Piece them together.
Reply 2
Original post by Blazy
You seem to have some confusion about fractions here...

Step 1) Note 1abc=1a×1b×1c \displaystyle \frac{1}{abc} = \frac{1}{a} \times \frac{1}{b} \times \frac{1}{c}

Step 2) What's the definition of sec(x) \displaystyle \sec(x) ? What about cot(x) \displaystyle \cot(x) ?

Piece them together.

I have managed to work it out from one side but not the other ...1475090085804952323006.jpg thanks
Reply 3
cos2y is 1/sec2y, like you said on the left. Just apply that to the RHS as well and you should be sorted - don't just change the cot term
Well, you have to recall that
sec2x=1/cos2x and
cot2x=1/tan2x
Reply 5
Original post by bstone13
cos2y is 1/sec2y, like you said on the left. Just apply that to the RHS as well and you should be sorted - don't just change the cot term


how can I get cos2y at the bottom? I only have cos^2 2y at the top of my fraction and this wouldn't give me sec2y... Thanks
Reply 6
Original post by coconut64
how can I get cos2y at the bottom? I only have cos^2 2y at the top of my fraction and this wouldn't give me sec2y... Thanks


image.jpg

You have to go back to the beginning. You didn't sub in for cos2y when you should have.

Does it make sense now?

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