Help physics

Draw ur normal where its about to enter the glass, as glass has higher refractive index the ray will bend towards the normal, as the ray approaches the lther side of the glass draw a normal ath the point wher it touches. As air has a lower refractive index than glass the ray will bend away from the normal.

For the second bit u draw the light ray entering and leaving the block then connect the two lines via one straight line

I don't understand the (b) part of the question, how will the paper make a difference?

Thanks.

Hi!

1. Place the block on paper.
2. Shine the light through the glass (DO NOT MOVE THE LIGHT SOURCE OR THE GLASS WHILE DOING IT)
3. 'Trace' the path of the light using pencil as it enters the glass; do the same as it exits
4. Then simply join the two ends of the line with a ruler; that'd be the ray through the glass.

Hope it helped and ask me if that didn't clear the doubt!

(cant believe i missed this..) Also, trace the sides of the glass block so that you can draw the normals and calculate the necessary data.

I dont get it , isnt that what the first part asks to do ? the second part is asking that if a paper would make difference and if so add that to the diagram, this question is so confusing

It seems to me that the second part is the first part of the question asking you to do the same on a piece of paper.

And no, the paper will not make a difference (I don't see why it would though )

It seems to me that the second part is the first part of the question asking you to do the same on a piece of paper.

And no, the paper will not make a difference (I don't see why it would though )

lol thats the exact thing confusing me . If the paper does not make a difference why would they ask us to draw on the same diagram if the answer would be same .Like they say how would u draw the path, if it is already asked and drawn in the first part ?

No, I think it's asking what would happen if you placed this transparent block on to a piece of paper. Of course, if it was a single piece of paper, a reasonable proprtion of the light would penetrate. In a mechanical sense however, said piece of paper would likely be on a desk or some other such structure. Said structure would also reflect the light. I guess we can assume the paper is 100% reflective, as I mentioned before. Always state your assumptions, then assuming your logic is correct, you can never be wrong.

I think the second part is the practical approach that is, how would you accurately calculate the refractive index (using simple apparatuses). For the first part you can draw just any line but that wouldn't help you get the actual value of the refractive index.

Correct me if I'm wrong but the question says a ray of light passing through the block. The most ideal thing that produces a (reasonable) ray of light is a LASER torch. If you shine the ray through the block I really don't see why the light would be reflected by the paper (assuming that the block is sitting on the paper) since you're passing the ray from the side of the block not from the top.

I think you're in the weeds here. It's clearly a high school question. As I said, there are many deeper consequences as to what will happen. However, of course the paper will reflect a large proportion of the light energy. Certainly orders of magnitude more then the block itself. Indeed, the block itself will reflect and refract energy in many and multiple directions.

At this level however, we're looking at the simplistic reactions of the light energy.

The difference between them is that The first question is checking if they know how which way towards the normal the light will bend. The second question is checking practical skills and if they know how to actually draw the path of the light in an experimental setting

Wait what !? So the paper will effect the light ray ? but how ?

Wait what !? So the paper will effect the light ray ? but how ?