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    So tomorrow we're meant to be doing PAG 1.2, Determination of the Relative Atomic Mass of Magnesium. I understand the experiment method but I don't know how you're meant to work out the relative atomic mass just from doing an experiment? Help please!
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    You will be given mass of Magnesium. Then you will also be given a solution that you mix the magnesium with.
    For example I am given 2.6g of magnesium and I mix it with 50cm3 of 0.2moldm-3 HCl. Work out the relative atomic mass of Magnesium.
    Work out moles of HCl 0.05 * 0.2 = 0.01 moles of HCL.
    You will need the reaction equation 2HCL + Mg ---> MgCl2 + H2

    I need to half the moles because of the 2:1 ratio. 0.01/2 = 0.005 moles
    then use Mass/ Moles = relative atomic mass

    I made this whole thing up, this is just to give you an idea. The whole experiment can be anything, we did this, but were told to work out the element X by working out relative atomic mass. Just keep an eye open for the quantitative results and use formulas.

    Hope I am right and this makes sense. Good luck
 
 
 
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