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Mechanics help please

A block B of mass 2.7 kg is pulled at constant speed along a straight line on a rough horizontal floor.
The pulling force has magnitude 25 N and acts at an angle of 1 above the horizontal. The normal
component of the contact force acting on B has magnitude 20 N.
(i) Show that sin 1 = 0.28.
(ii) Find the work done by the pulling force in moving the block a distance of 5 m

Now i was able to do part (i), but in part (ii) the answer is 120, but i get 75 because i do FdcosQ = 25*cosQ*5 = 25 * 0.6 * 5 where 25*0.6 gives the horizontal force as per the direction the block moves

Reply 1

the bear

Original post by Revision99

A block B of mass 2.7 kg is pulled at constant speed along a straight line on a rough horizontal floor.
The pulling force has magnitude 25 N and acts at an angle of Θ above the horizontal. The normal
component of the contact force acting on B has magnitude 20 N.
(i) Show that sin Θ = 0.28.
(ii) Find the work done by the pulling force in moving the block a distance of 5 m

Now i was able to do part (i), but in part (ii) the answer is 120, but i get 75 because i do FdcosQ = 25*cosΘ*5 = 25 * 0.6 * 5 where 25*0.6 gives the horizontal force as per the direction the block moves