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    Please can someone help me with Q)27?

    On one track I solved that 'x'(the input value), would be greater than 1/8 which would fit the statement. However x>1/8 is not a range of values, so I decided to go down another route.

    I factorised x^2-8x+16 then decided to square root both sides. However I think I got lost because my final form doesn't make much sense.

    Would it be right if I went with my first option but wrote it as:
    x is greater than 1/8 but less than or equal to infinity? Am i missing something?

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    Wheres the question?
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    (Original post by Y11_Maths)
    However x>1/8 is not a range of values
    Yes it is. Question done.

    \frac{1}{8} < x < \infty if you really want but no need.
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    Oh I can see it now. You're working from the first part is correct, no need to do anything else.
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    (Original post by RDKGames)
    Yes it is. Question done.
    Oh haha thanks 😅
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