unit 1 chem
in 2015 question no.13
in an experiment 3.425g of lead oxide was reduced to form 3.105g of lead.
empirical formula of the lead oxide?
1)PbO
2)Pb3O2
3)Pb3O4
4)Pb4O3
the answer is 3rd one .but idk how to get it though ? could someone help with this?
in an experiment 3.425g of lead oxide was reduced to form 3.105g of lead.
empirical formula of the lead oxide?
1)PbO
2)Pb3O2
3)Pb3O4
4)Pb4O3
the answer is 3rd one .but idk how to get it though ? could someone help with this?
Original post by Believerrrr
in 2015 question no.13
in an experiment 3.425g of lead oxide was reduced to form 3.105g of lead.
empirical formula of the lead oxide?
1)PbO
2)Pb3O2
3)Pb3O4
4)Pb4O3
the answer is 3rd one .but idk how to get it though ? could someone help with this?
in an experiment 3.425g of lead oxide was reduced to form 3.105g of lead.
empirical formula of the lead oxide?
1)PbO
2)Pb3O2
3)Pb3O4
4)Pb4O3
the answer is 3rd one .but idk how to get it though ? could someone help with this?
I don't know for sure, but the question seems to give you how much lead there is vs oxygen. So you need to number of moles of each and work out their ratio
Original post by Believerrrr
in 2015 question no.13
in an experiment 3.425g of lead oxide was reduced to form 3.105g of lead.
empirical formula of the lead oxide?
1)PbO
2)Pb3O2
3)Pb3O4
4)Pb4O3
the answer is 3rd one .but idk how to get it though ? could someone help with this?
in an experiment 3.425g of lead oxide was reduced to form 3.105g of lead.
empirical formula of the lead oxide?
1)PbO
2)Pb3O2
3)Pb3O4
4)Pb4O3
the answer is 3rd one .but idk how to get it though ? could someone help with this?
pb: 3.105/207.2 =0.01499...
o: (3.425-3.105)/16 =0.02
Divide everything by 0.01499 to get.
pb=1
o=1.33..
Next times everything by 3 to get whole numbers, so....
1.33...*3= 4.0036..
1*3 =3
TherforePb3o4
Hope this helps
Original post by iamthelemon
pb: 3.105/207.2 =0.01499...
o: (3.425-3.105)/16 =0.02
Divide everything by 0.01499 to get.
pb=1
o=1.33..
Next times everything by 3 to get whole numbers, so....
1.33...*3= 4.0036..
1*3 =3
TherforePb3o4
Hope this helps
o: (3.425-3.105)/16 =0.02
Divide everything by 0.01499 to get.
pb=1
o=1.33..
Next times everything by 3 to get whole numbers, so....
1.33...*3= 4.0036..
1*3 =3
TherforePb3o4
Hope this helps
ohhhh i rounded off 1.333 to 1
now i get it !! thank you so much !!
Original post by Believerrrr
ohhhh i rounded off 1.333 to 1
now i get it !! thank you so much !!
now i get it !! thank you so much !!
No worries,glad i know some chemistry before my A-levels
Original post by iamthelemon
pb: 3.105/207.2 =0.01499...
o: (3.425-3.105)/16 =0.02
Divide everything by 0.01499 to get.
pb=1
o=1.33..
Next times everything by 3 to get whole numbers, so....
1.33...*3= 4.0036..
1*3 =3
TherforePb3o4
Hope this helps
o: (3.425-3.105)/16 =0.02
Divide everything by 0.01499 to get.
pb=1
o=1.33..
Next times everything by 3 to get whole numbers, so....
1.33...*3= 4.0036..
1*3 =3
TherforePb3o4
Hope this helps
HI
I've got a q is their a reason u decided by 0.01499
Original post by Mojamal2007
HI
I've got a q is their a reason u decided by 0.01499
I've got a q is their a reason u decided by 0.01499
Hi @Mojamal2007,
Thank you for posting in the Chemistry Forum.
However, please be aware that this thread is 5 years old. We generally avoid reviving old threads, as there's a risk that posts may go unnoticed when threads are several years old and already have responses.
Do you understand the steps prior to that step? If you'd like, I'd be happy to assist you with the question mentioned above after moving your post to its own separate thread. Do let me know if you would like me to do this.
Once again, thank you for posting and we hope to see more of your threads around the Chemistry Forum.
5hyl33n
(edited 7 months ago)
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