# edexcel C2 23rd May 2018 unofficial mark schemeWatch

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11 months ago
#61
Isn’t 7 625.563? Not 625056
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11 months ago
#62
For 1) can you write 4rt2 as a decimal as that’s what my calculator gave me it in ??
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11 months ago
#63
(Original post by Manuster)
This is right
Lol I kept plugging it in and I kept getting 7175.7??
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11 months ago
#64
(Original post by oscar gul)
no as r is -0.9 so 1-(-0.9) is 1.9
but as r<1 you need to take the modulus and therefore it’s 1-|-.09| which is 1-0.9? then 10000x0.1 is 1000.
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11 months ago
#65
(Original post by shivalakhani)
1) (2,2) and (6,4rt2)
b) r=51.413
2) 128 + 448x +672k^2x^2 +560k^3x^3
b) k=1.5
3) proof
b) a+b=21
c) b=31 a=-10
d) 24x^2 - 34x + 31
4) Area = 8.75
b) Flag area=20.02
c) 26.79
5) centre-(1,-7)
b) r=5rt2
c) y=0 and y=-14
d) x+7y-2=0
6) a=19000
b) U5=12465.9
c) S12=7176
7) y=625056
a) proof
b) x=1/3
8) x=248.6 , 331.4 (degrees)
ii) theta= 0.258 , 2.89 , 3.48 , 5.94
9) A(4,112)
b) (25/4,0)
c) r=79.77

(btw I tutor even over Skype msg me for details)
If i got 100% until question 9 and got most of 9 wrong is it still possible to get an A?
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11 months ago
#66
(Original post by tayreed)
but as r<1 you need to take the modulus and therefore it’s 1-|-.09| which is 1-0.9? then 10000x0.1 is 1000.
-0.9 is less than 1?
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3
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11 months ago
#67
Isn’t 8(I) 0.253 radians (3 significant figures)
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1
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11 months ago
#68
(Original post by oscar gul)
-0.9 is less than 1?
yeah? that’s what i said
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11 months ago
#69
I got the wrong value of A for the sequence one, is there likely to be error carried forward?
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11 months ago
#70
(Original post by IgnoreMyName)
Im pretty sure With A at 19,000, R=-0.9 and the sum of the first 12 terms, putting them together into the equation, you get 12824.29356. Not the 7,176 whatever you wrote..
6c) Is surely wrong, because i keep plugging it in, and i get the same 12,824 not 7176
Anyone who got 7176 has failed it’s deep
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11 months ago
#71
(Original post by IgnoreMyName)
Im pretty sure With A at 19,000, R=-0.9 and the sum of the first 12 terms, putting them together into the equation, you get 12824.29356. Not the 7,176 whatever you wrote..
6c) Is surely wrong, because i keep plugging it in, and i get the same 12,824 not 7176
Omgggg yeah same where’s everyone getting 7176 from
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2
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11 months ago
#72
What was question 7?
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11 months ago
#73
what is question 7?
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11 months ago
#74
How many marks was part B for the last Q
0
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11 months ago
#75
(Original post by shivalakhani)
1) (2,2) and (6,4rt2)
b) r=51.413
2) 128 + 448x +672k^2x^2 +560k^3x^3
b) k=1.5
3) proof
b) a+b=21
c) b=31 a=-10
d) 24x^2 - 34x + 31
4) Area = 8.75
b) Flag area=20.02
c) 26.79
5) centre-(1,-7)
b) r=5rt2
c) y=0 and y=-14
d) x+7y-2=0
6) a=19000
b) U5=12465.9
c) S12=7176
7) y=625056
a) proof
b) x=1/3
8) x=248.6 , 331.4 (degrees)
ii) theta= 0.258 , 2.89 , 3.48 , 5.94
9) A(4,112)
b) (25/4,0)
c) r=79.77

(btw I tutor even over Skype msg me for details)
You’re a tutor? Did you take the exam? Or are you a teacher??
Basically want to know if you have the actual exam paper on you. Can’t remember the question so if you have it it would rly help
1
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11 months ago
#76
7176 is right
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2
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11 months ago
#77
Would 71 marks be guaranteed 100 UMS?
0
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11 months ago
#78
I got 120 something for the very last question
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11 months ago
#79
what was the sequence part b and part c out of please
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11 months ago
#80
(Original post by tayreed)
but as r<1 you need to take the modulus and therefore it’s 1-|-.09| which is 1-0.9? then 10000x0.1 is 1000.
No it says that r is less than 1... 1>-0.9

So what's the issue?
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