a car accelerates uniformly at 2 m/s^2 for 10 seconds. if the rider starts from rest ,work out the distance travelled in the sixth second(between 5 and 6)?
I have worked out the distance travelled in the 10 seconds using s=ut+0.5at^2 but idk what the distance is after at the 6th second ( it's not 36)
we need to work out the velocity at 6 seconds, so V= u + at 0+2x10 = 20 using s = vt - 1/2at^2 i got 84, not sure if its right though we'd need some physics person to help. (tag me in the real answer please)
Why not just work out the distance for 6seconds and then the distance for 7 seconds then do the 7 sec - 6 sec = distance travelled in the sixth second? In this case it would be 49 - 36 = 13m Unless you mean something different
a car accelerates uniformly at 2 m/s^2 for 10 seconds. if the rider starts from rest ,work out the distance travelled in the sixth second(between 5 and 6)?
I'd refuse to answer. You don't ride a car
I'd consider the time, t′, to start at t=5, so put u=10ms−1 (from v=u+at) and t′=1 into this: s=ut′+2at′2
Why not just work out the distance for 6seconds and then the distance for 7 seconds then do the 7 sec - 6 sec = distance travelled in the sixth second? In this case it would be 49 - 36 = 13m Unless you mean something different
The sixth second is that between t=5 and 6, not 6 and 7.
If you want to this approach, then you'd do:
s=ut+2at2=2at2
st=5=2at2=.. st=6=2at2=..
And calculate the difference. That works, as does the method that I outlined earlier.