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Don’t understand this question!!

for part c, I thought that you’d sub in x=-5 to dy/dx to get the gradient (which is 20) and then get the negative reciprocal because it’s a tangent. apparently the gradient for that point is just 20 and not -1/20 ? please help.
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but dy/dx gives the gradient of tangent, not the gradient of the normal

the gradient of the normal is -1/m where m is the gradient of the tangent
oh, I thought dy/dx gave the gradient of the curve at that point so the tangent would be the negative reciprocal. thank you!

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