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binomial expansion

Screen Shot 2019-05-05 at 14.07.39.png

why wouldn't the range of validity not be x<1/4
Original post by jeriu
Screen Shot 2019-05-05 at 14.07.39.png

why wouldn't the range of validity not be x<1/4

You don;t need a binomial expansion for that. (1 - 4x)(1 - 4x)(1 - 4x) ....
Original post by jeriu


why wouldn't the range of validity not be x<1/4


Nope. It's valid for all xx.

If it was (14x)3(1-4x)^{-3} then the range of validity would be x<14|x| < \dfrac{1}{4}.
(edited 4 years ago)
Reply 3
Original post by RDKGames
Nope. It's valid for all xx.

If it was (14x)3(1-4x)^{-3} then the range of validity would be x<14|x| < \dfrac{1}{4}.


why may i ask
Original post by jeriu
why may i ask


(14x)3(1-4x)^3 can be expressed as 112x+48x264x31-12x + 48x^2 - 64x^3. This is a finite sum for any xx you put in, so it always converges onto a value.

(14x)3(1-4x)^{-3} cannot be expressed as a finite sum. It constitutes an infinite one, and with infinite sums, they converge only under certain conditions. For forms like these, this condition is precisely that we must have xx as part of a certain interval.

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