use V=U+at where v=0 at the maximum height, work out t using the vertical component of velocity and sub into s=ut+1/2at^2
then for the range use 2t as the projectile uses parabolic motion and sub in horizontal component of velocity.

Reply 45

obanks1

4

Difficult but manageable. Did anyone get the Trig proof?

Reply 46

Grumpi

7

Oh no lol i got 4i+107j
How did you do it?

Original post by Mermaidqueen

me too!

Reply 47

maxwell40

I got that at the start - I think you missed the weight of the particle acting on it and only used the two given forces?

Original post by Grumpi

Oh no lol i got 4i+107j
How did you do it?

Reply 48

honeydukes01

15

Has anyone else’s school complained the OCR about the mistake?

Reply 49

elavela

4

it was for the binomial expansion question, I think it was question 3, where you then equate coefficients of x and x^2

Original post by sajitha123

what was the a for?

Reply 50

elavela

4

did anyone get that the beam doesnt tip because the minimum length from q in order to tip was about like 0.7.. which was bigger than the beam?

Reply 51

Grumpi

7

Hmmm i think you're right. Did they give you the mass at the start?

Original post by maxwell40

I got that at the start - I think you missed the weight of the particle acting on it and only used the two given forces?

Reply 52

C342

8

Original post by Mikeyhiggs

I got a different coefficient. About 0.2 ish

sameee

Reply 53

honeydukes01

15

Original post by danstollenwerk

What mistake?

In the parametric question

Reply 54

amartyasen

13

I got that too... Can't remember the exact distance but it was greater than the distance from the point of support at Q to the end of the beam assuming the reaction was 0 from the other pivot. Which would mean it wouldn't tip

Original post by elavela

did anyone get that the beam doesnt tip because the minimum length from q in order to tip was about like 0.7.. which was bigger than the beam?

Reply 55

NaomiWilso

6

Original post by honeydukes01

In the parametric question

What was wrong with it

Reply 56

Dr..D

11

Original post by amartyasen

I got that too... Can't remember the exact distance but it was greater than the distance from the point of support at Q to the end of the beam assuming the reaction was 0 from the other pivot. Which would mean it wouldn't tip

I assumed the reaction was zero too
I assumed first that the reaction at q is zero and then I took moments at q and I assumed that p was zero and I think one of them gave me a negative distance
and I don't remember the other one tho lol

Reply 57

ravman123456

11

What did people get for the moments question

Reply 58

honeydukes01

15

Original post by NaomiWilso

What was wrong with it

The text above describing the graphs was wrong - one of the equations was incorrect

Reply 59

MrMoment

OP

13

I did moments from reaction at q with x the distance to 50g weight.

Got x=0.072 or something

And as the distance is 0.3m, it’ll tip when less than 0.224m from that end.

OCR MEI Maths: Paper 1, Unofficial mark scheme

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