The Student Room Group

chem a level question

does anyone know how to answer this qestion?

When one mole of ammonia is heated to a high temperature, 50% dissociates according to the following equilibrium.
2NH3(g) N2(g) + 3H2(g)

What is the total number of moles of gas present in the equilibrium mixture?

the answer is 1.5

thanks
So, think about how many moles of each you had before the eqb was established.

You had 1mol of NH3, and 0 of N2 and 0 of H2

When it reached eqb, 1/2 of the 1mol of NH3 disassociates whilst the other 1/2 remains as 0.5 mol of NH3.

Since there are two moles of NH3, you divide that 0.5 by 2 to find what each mol is, if that makes sense?? So, 0.5/2 = 0.25

One mole of N2 ----> 1 * 0.25 = 0.25 mol
3 mole of H2 -------> 3 * 0.25 = 0.75

0.75 + 0.25 + 0.5 = 1.5 mol all together.

I hope this made sense (I'm sorry if my explanation is a bit dodgy lol)
Reply 2
Original post by he3456
does anyone know how to answer this qestion?

When one mole of ammonia is heated to a high temperature, 50% dissociates according to the following equilibrium.
2NH3(g) N2(g) + 3H2(g)

What is the total number of moles of gas present in the equilibrium mixture?

the answer is 1.5

thanks


How about this:

If none dissociated, you'd still have 1 mol.

If all dissociated, you'd have 2 mol (since 2 mol of reactant turns into 4 mol of products)

If half of the reactant doesn't dissociate and half does...
Reply 3
Original post by inoubliable
So, think about how many moles of each you had before the eqb was established.

You had 1mol of NH3, and 0 of N2 and 0 of H2

When it reached eqb, 1/2 of the 1mol of NH3 disassociates whilst the other 1/2 remains as 0.5 mol of NH3.

Since there are two moles of NH3, you divide that 0.5 by 2 to find what each mol is, if that makes sense?? So, 0.5/2 = 0.25

One mole of N2 ----> 1 * 0.25 = 0.25 mol
3 mole of H2 -------> 3 * 0.25 = 0.75

0.75 + 0.25 + 0.5 = 1.5 mol all together.

I hope this made sense (I'm sorry if my explanation is a bit dodgy lol)

ah, thank you, it definitely made sense :biggrin:

Quick Reply

Latest