Original post by Shas72
e^(3x+4y)=2e^(2x-y)
e^(2x+y)=8e^(x+6y)
Solve the simulteneous equation giving your ans in exact form
e^(2x+y)=8e^(x+6y)
Solve the simulteneous equation giving your ans in exact form
What rules did you learn for manipulating powers, in GCSE?
Original post by David Getling
What rules did you learn for manipulating powers, in GCSE?
So you do e^3x×e^4y×e^y/e^2x =2
Original post by Shas72
So you do e^3x×e^4y×e^y/e^2x =2
And what is the rule for dividing powers?
Original post by David Getling
And what is the rule for dividing powers?
So I got e^(x+5y)=2 and e^(x-5y)=8
Original post by David Getling
And what is the rule for dividing powers?
Thanks a lot
Original post by David Getling
And what is the rule for dividing powers?
Can you also pls help me with one more problem
Solve ln(2x+1)<ln(x+4)
When I did this I get only x<3 , but the ans is -1/2<x<3
Original post by Shas72
Can you also pls help me with one more problem
Solve ln(2x+1)<ln(x+4)
When I did this I get only x<3 , but the ans is -1/2<x<3
Solve ln(2x+1)<ln(x+4)
When I did this I get only x<3 , but the ans is -1/2<x<3
What is the domain of ln?
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