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Chemistry

klb9

Calculate the concentration of the calcium hydroxide in mol/dm3 the equation is: 2HCL+CA(OH)2 = CACL2+2H20

Reply 1

klb9

Original post by Chemastronomical

Do you have any values for the starting materials?

25cm3 for calcium hydroxide was titrated against 0.100 mol/dm3 of Hydrochloric acid and 26.3cm3 of the Hydrochloric acid was needed to neutralise the calcium hydroxide

Reply 2

username5211340

Sorry for the late reply,

Ok so we’re using the following formula, n=CV.

concentration(Ca(OH)2 = n/V and we have the volume therefore we can write = n/0.025

we need the number of moles, the questions given us the volume and concentration of HCl so we can use the formula to find the number of moles...

n(HCl) C*V = 0.1 * 0.0263 = 0.00263

Due to the following rations ( 2 HCl to 1 Ca(OH)2 ) we have HALF the moles of HCl so we say:

number of moles for Ca(OH)2 is 0.00263/2 = 0.001315 moles...

Going back to the first step:

concentration(Ca(OH)2 = n/V and we have the volume therefore we can write = 0.001315/0.025 =

0.0526 mol dm-3