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How can I find the roots of y = arcsin(x) + pi/2 ?

seals2001

I have tried to find the roots by substituting in x = 0 , but for some reason this gives me the intercept of the graph with the vertical axis ?

Thanks.

Reply 1

RDKGames

Study Forum Helper

Original post by seals2001

I have tried to find the roots by substituting in x = 0 , but for some reason this gives me the intercept of the graph with the vertical axis ?

Thanks.

But roots occur where y=0 instead.

Reply 2

seals2001

Original post by RDKGames

But roots occur where y=0 instead.

I am being so stupid, thank you.

(edited 3 years ago)

Screenshot 2020-09-25 at 12.05.51.png121.3KB

Reply 3

RDKGames

Study Forum Helper

Original post by seals2001

I have plotted the graph so that x is on the y axis and also y is on the x axis.

Like this but transformed :

So I want where theta is zero to find the "root" on the graph ?

You are overthinking it, and I do not understand your post here.

A root x=x* of y=f(x) satisfies 0=f(x*).

So the root of y=arcsin(x)+pi/2 is obtained by solving

0 = arcsin(x) + pi/2