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Statistics: How to find standard deviation and mean if you only know ∑x and ∑x^2

The actual question is:
The daily mean wind speed, x (kn) for Leeming is recorded in June 2015. The summary of the data is:
∑x = 243 and ∑x^2= 2317

a)use your calculator to work out the mean and standard deviation of the daily mean wind speed in June 2015.

I don't understand how I'm supposed to do this if I don't know the frequency or wind speeds?
I see, very obvious now, I didn't think about the number of days in June.
Original post by HowQuestionMark
The actual question is:
The daily mean wind speed, x (kn) for Leeming is recorded in June 2015. The summary of the data is:
∑x = 243 and ∑x^2= 2317

a)use your calculator to work out the mean and standard deviation of the daily mean wind speed in June 2015.

I don't understand how I'm supposed to do this if I don't know the frequency or wind speeds?

You need the number of samples (days in June). You can then calculate the SD:

σ2=1n(xxˉ)2{\sigma}^2=\frac{1}{n}\sum{(x-\bar{x})^2}

nσ2=(x22xxˉ+xˉ2)=..\therefore n {\sigma}^2=\sum{(x^2-2x \bar{x}+\bar{x}^2)}=..

Use xˉ=1nx\bar{x}=\frac{1}{n}\sum{x}
(edited 3 years ago)
Original post by RogerOxon
You need the number of samples (days in June). You can then calculate the SD:

σ2=1n(xxˉ)2{\sigma}^2=\frac{1}{n}\sum{(x-\bar{x})^2}

nσ2=(x22xxˉ+xˉ2)=..\therefore n {\sigma}^2=\sum{(x^2-2x \bar{x}+\bar{x}^2)}=..

Use xˉ=1nx\bar{x}=\frac{1}{n}\sum{x}

I see, I also have another question that says:
The maximum wind speed was 17kn and lowest was 4kn.
Estimate the number of days in which the wind speed was greater than one standard deviation above the mean and state one assumption you made in producing the estimated.
I worked out the mean+standard deviation to be 11.51.
Would you mind just telling me what I need to do here as well?
Yes I am
oh! Thats so useful. Thank you so much!!

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