The Student Room Group
Reply 1
2/(1 - r) = 5
1 - r = 2/5
r = 3/5

--

d = 5.9 - 7 = -1.1

S(n)
= sum of first n terms
= (1/2)n[first term + nth term]
= (1/2)n[7 + (7 - 1.1(n - 1))]
= (1/2)n[14 - 1.1(n - 1)]

S(n) is negative when

14 - 1.1(n - 1) < 0
(n - 1) > 14/1.1
n > 14/1.1 + 1

Smallest such value of n = 14

Latest