The Student Room Group

Query with forces in 2 dimensions

I understand how to get angles and forces in a scenario where a particle of X mass is being pulled up a slope of θ° with a force of F, but now a friction force is also involved, usually parallel to the slope. How do I go about including this additional force in equations.

Example: A mass of 20kg is being pulled up a slope at 14° to the horizontal. A force of 70N pulls the object at an angle of θ° at a constant speed, despite the 10N of friction. Find θ

I tried 70cos(θ) = 200sin(14) but that answer is slightly off, so I know I need to incorporate the 10N of friction somewhere, but I'm not sure how.
Reply 1
if you resolve the forces going up the slope using f=ma you would get 70cos(theta)-20gsin(14)-10=0
you just need to include all the forces, positive and negative that are acting in the direction you are resolving
yes that worked great, thank you very much!

Quick Reply

Latest