AS level chemistry
Aqueous sodium iodide reacts with aqueous silver nitrate to form a precipitate of silver iodide.
NaI(aq) + AgNO3(aq) → NaNO3(aq) + AgI(s)
Mr values: 149.9,169.9,85.0,234.8
What is the percentage atom economy by mass for the production of silver iodide in this reaction?
A 29%
B 37%
C 50%
D 73%
The answer is D but i don't know how
NaI(aq) + AgNO3(aq) → NaNO3(aq) + AgI(s)
Mr values: 149.9,169.9,85.0,234.8
What is the percentage atom economy by mass for the production of silver iodide in this reaction?
A 29%
B 37%
C 50%
D 73%
The answer is D but i don't know how
(edited 3 years ago)
Because atom eco is sum of desired product divided by the sum of all reactants
so 149.9 + 169.9 = 319.8
the sum of desired product is 234.8
so using the equation you should be able to find the answer, which is correctly D
so 149.9 + 169.9 = 319.8
the sum of desired product is 234.8
so using the equation you should be able to find the answer, which is correctly D
Original post by a.f.x.d
Aqueous sodium iodide reacts with aqueous silver nitrate to form a precipitate of silver iodide.
NaI(aq) + AgNO3(aq) → NaNO3(aq) + AgI(s)
Mr values: 149.9,169.9,85.0,234.8
What is the percentage atom economy by mass for the production of silver iodide in this reaction?
A 29%
B 37%
C 50%
D 73%
The answer is D but i don't know how
NaI(aq) + AgNO3(aq) → NaNO3(aq) + AgI(s)
Mr values: 149.9,169.9,85.0,234.8
What is the percentage atom economy by mass for the production of silver iodide in this reaction?
A 29%
B 37%
C 50%
D 73%
The answer is D but i don't know how
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