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Struggling with a maths question!

Hey! Just quickly wanted to ask how I would integrate -(4)/(3+2u) ?
Thank you!

I think you would take out the -4 to get -4(1/(3+2u)) then I think it would be -4(ln (3+2u))
But I’m not sure.
There is a great website called integral calculator which does it for you and shows the method so maybe check on there

Reply 2

Grave124

Original post by Smouncher

Thank youuu! :smile:

Reply 3

username5746858

Original post by Grave124

Hey! Just quickly wanted to ask how I would integrate -(4)/(3+2u) ?
Thank you!

If you use your brain you will find it is -2 LN (3+2u) + C
ALWAYS REMEMBER THE C

Reply 4

Grave124

Original post by jimngeoff

If you use your brain you will find it is -2 LN (3+2u) + C
ALWAYS REMEMBER THE C

why so passive aggressive lmao but cheers!

Reply 5

username5746858

Original post by Grave124

why so passive aggressive lmao but cheers!

L M A O

Reply 6

davros

Original post by Grave124

Hey! Just quickly wanted to ask how I would integrate -(4)/(3+2u) ?
Thank you!

You may find this is listed as a standard integral.

If not, then:

assuming you're integrating with respect to u, consider that the integral of 1/u is just ln u (+ a constant). So try differentiating ln(3 + 2u) and see what adjustment you would need to make to get the thing you're trying to integrate :smile: