chemistry a-level, percentage yield question
i was unsure about how to go with this question and was wondering if anyone could help?
CuO + H2SO4 + 4H2O → CuSO4•5H2O
Calculate the mass of hydrated copper sulfate produced from 21.9 g of copper oxide if the percentage yield for the reaction was 82.1%.
so far i've worked out the number of moles for copper oxide which was 0.28 (21.9/79.5). this means the theoretical yield for the copper sulphate should be 0.28 too? from this i set up a formula to work out the actual yield:
actual yield/0.28 x 100 = 82.1%
but i dont know how to find the actual yield from it so i can multiply it by the Mr of copper sulphate and get the mass.
CuO + H2SO4 + 4H2O → CuSO4•5H2O
Calculate the mass of hydrated copper sulfate produced from 21.9 g of copper oxide if the percentage yield for the reaction was 82.1%.
so far i've worked out the number of moles for copper oxide which was 0.28 (21.9/79.5). this means the theoretical yield for the copper sulphate should be 0.28 too? from this i set up a formula to work out the actual yield:
actual yield/0.28 x 100 = 82.1%
but i dont know how to find the actual yield from it so i can multiply it by the Mr of copper sulphate and get the mass.
You are really close. Next find 82.1% of o 0.28.
yep i worked it out to get 0.22988 mol, multiplied it by the Mr and got 36.7g. thank you!
Original post by ultimateslayer30
yep i worked it out to get 0.22988 mol, multiiplied it by the Mr and got 36.7g. thank you!
I get 57 g.
I agree with illuminate. The Mr should be about 250.
Original post by Old man1234
I agree with illuminate. The Mr should be about 250.
i'm a bit confused, am i not trying to find the Mr of copper sulphate, how did the Mr end up as 250
Hydrated copper sulphate' the Mr includes the 5 water molecules?
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