Original post by Hiim
yes. its always the angle to the normal.
But on the mark scheme it says the refractive index is sin 77/sin 47 but shouldn’t it be the other way round because 47 is the angle of incidence? Thanks!
use equation:
n_1*sin(theta_1) = n_2*sin(theta_2)
theta_1 is 47, theta_2 is 77 and n_2 is 1 (because the refractive index of air is 1)
therefore you can rearrange this to find n_1:
n_1 = sin(77)/sin(47)
hopefully this helps!
n_1*sin(theta_1) = n_2*sin(theta_2)
theta_1 is 47, theta_2 is 77 and n_2 is 1 (because the refractive index of air is 1)
therefore you can rearrange this to find n_1:
n_1 = sin(77)/sin(47)
hopefully this helps!
Original post by iTsJames123
use equation:
n_1*sin(theta_1) = n_2*sin(theta_2)
theta_1 is 47, theta_2 is 77 and n_2 is 1 (because the refractive index of air is 1)
therefore you can rearrange this to find n_1:
n_1 = sin(77)/sin(47)
hopefully this helps!
n_1*sin(theta_1) = n_2*sin(theta_2)
theta_1 is 47, theta_2 is 77 and n_2 is 1 (because the refractive index of air is 1)
therefore you can rearrange this to find n_1:
n_1 = sin(77)/sin(47)
hopefully this helps!
Hi thank you so much for this! Since this is a gcse question, would there be any way to do this with just n= sin i/sin r?
The equation n_1*sin(theta_1) = n_2*sin(theta_2) is used in gcse.
https://astarmathsandphysics.com/gcse-physics-notes/816-snell-s-law-refraction-total-internal-reflection-and-the-critical-angle.html
https://isaacphysics.org/concepts/cp_reflection_and_refraction?stage=all
Also n = sin i/sin r calculates n_2 rather n_1.
https://astarmathsandphysics.com/gcse-physics-notes/816-snell-s-law-refraction-total-internal-reflection-and-the-critical-angle.html
https://isaacphysics.org/concepts/cp_reflection_and_refraction?stage=all
Also n = sin i/sin r calculates n_2 rather n_1.
(edited 11 months ago)
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