I have solved part A and B but don't know about C. I thought you could use the sine rule on the triangle formed by h, R and the refracted ray such that h/(180-theta)=R/(sin(theta-2*theta_g+90) and rearrange for h. However then the denominator is not in the required form of cos(2*theta_g-theta) and I don't think it's the correct way to get h anyway. Any help would be appreciated.
I have solved part A and B but don't know about C. I thought you could use the sine rule on the triangle formed by h, R and the refracted ray such that h/(180-theta)=R/(sin(theta-2*theta_g+90) and rearrange for h. However then the denominator is not in the required form of cos(2*theta_g-theta) and I don't think it's the correct way to get h anyway. Any help would be appreciated.
Without looking at the question itself, starting from your expression, consider some simple trig. transformations.
I have solved part A and B but don't know about C. I thought you could use the sine rule on the triangle formed by h, R and the refracted ray such that h/(180-theta)=R/(sin(theta-2*theta_g+90) and rearrange for h. However then the denominator is not in the required form of cos(2*theta_g-theta) and I don't think it's the correct way to get h anyway. Any help would be appreciated.
Without looking at the question itself, starting from your expression, consider some simple trig. transformations.
E.g what's sin(x+90) ?
Then one other.
Oh yes thank you that helps but it’s still incorrect.